The answer would be 219.3 (:
Please mark me the brainliest ty
Answer:
147.5
Step-by-step explanation:
i multiplied then subtracted them ?im not sure tho
Answer:
A negative 2’s complement number is even precisely when its last digit is 0 as well.
Step-by-step explanation:
Proof part 1: Assume there exists a 2’s complement negative even number which ends with 1. We can, therefore, express this number as
1 ..... 1 = - (2’s complement of 1 ....1)
= - (0 ... 1 )
≠ even
Since we know precisely that a positive binary number is not even when it ends with a 1. This is a conflict with our assumption. Our assumption is, therefore, wrong.
Proof part 2: Assume there exists a 2’s complement negative odd number which ends with 0. We can, therefore, express this number as
1 ..... 0 = - (2’s complement of 1 ....0)
= - (0 ... 0 )
= even
Since we know precisely that a positive binary number is even when it ends with a 0. This is a conflict with our assumption. Our assumption is, therefore, wrong.
Answer:
a_{n} = a_{1} + (n-1)d
a_n = the nᵗʰ term in the sequence
a_1 = the first term in the sequence
d = the common difference between terms
The general term of an arithmetic sequence can be written in terms of its first term a1, common difference d, and index n as follows: an=a1+(n−1)d. ... The nth partial sum of an arithmetic sequence can be calculated using the first and last terms as follows: Sn=n(a1+an)2.
