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polet [3.4K]
2 years ago
14

4. Which point is labeled at (-2, 3)?

Mathematics
2 answers:
melisa1 [442]2 years ago
8 0

Answer:

G

Step-by-step explanation:

I hope this helps, have a great day:) God bless you!

pickupchik [31]2 years ago
3 0

Answer:

g

Step-by-step explanation:

bc you go from -2 then up the Y axis 3 times and its g

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Please answer this quickly
scZoUnD [109]

Answer:

14 and 16

Step-by-step explanation:

your adding 2 to each each time, if your looking for the multiplied awnser its 224

8 0
2 years ago
I WILL GIVE OUT BRAINELIST Quadratic functions g(x) and h(x) are graphed on the same coordinate grid. The vertex of the graph of
Soloha48 [4]

Answer:

  h(x)=(x-12)2 and g(x)=2

7 0
3 years ago
Josh has a rewards card for a movie theater. He receives 15 points for becoming a rewards card holder. He earns 3.5 points for e
Savatey [412]

Answer:

C. 55 \leq 3.5x + 15

Step-by-step explanation:

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6 0
3 years ago
Which one is correct
bekas [8.4K]

Answer:

Bart is correct

Step-by-step explanation:

5 0
2 years ago
A researcher compares differences in positivity between participants in a low-, middle-, or upper-middle-class family. If she ob
777dan777 [17]

Answer:

(2, 12)

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have 3 groups and on each group from j=1,\dots,n_j we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=k-1=3-1=2 where k =3 represent the number of groups.  

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-K=15-3=12.  

And the total degrees of freedom would be df=N-1=15 -1 =14  

And the correct answer would be 2 degrees of freedom for the numerator and 12 for the denominator

(2, 12)

3 0
3 years ago
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