This problem can be solved by manipulating the formula for power, which is: P = VI. Where:

P = Power in watts
V= Voltage in volts
I = Current in amperes

Since we are already given the power and voltage, simple substitution can be done.

P = VI
3.5 watts = 120 volts * I
I = 3.5 / 120
I = 0.0292 Amperes or 29.2 milliAmperes

Therefore, the current through the bulb is 29.2mA

5 0

3 years ago

The length of a rectangle is 3 yd less than twice the width, and the area of the rectangle is 44 yd^2 Find the dimensions of the

vovangra [49]

Answer:

width: 5.5 yd; length: 8 yd

Step-by-step explanation:

Let w represent the width of the rectangle in yards. Then 2w-3 is the length and the area is the product of length and width:

w(2w-3) = 44

2w^2 -3w -44 = 0 . . . . put the equation into standard form

(w+4)(2w -11) = 0 . . . . . factor the equation

w = -4 or 11/2 . . . . . . . . the negative solution is extraneous

Then the length is 2·(11/2) -3 = 8.

The width of the rectangle is 5.5 yards; the length is 8 yards.

5 0

3 years ago

On Monday Adam spent 61⁄3 hours studying. On Tuesday he spent another 31⁄2 hours studying. What is the combined time he spent st

Sedbober [7]

9 5/6 hours. Find a common denominator; 6.

3 0

3 years ago