Define i as a unit vector in the eastern direction.
Define j as a unit vector in the northern direction.
Part I
Because the wind is blowing west, its velocity vector is
-23i mph or as (-23, 0) mph
Because the plane is traveling north, its velocity vector is
200j mph or as (0, 200) mph
Part II
The actual velocity of the plane is the vector sum of the plane and wind velocities.
That is,
200j - 23i or (-23, 200) mph
Part III
The ground speed of the plane is the magnitude of its vector.
The ground speed is
√[200² + (-23)²] = 201.32 mph
The ground speed of the plane is 201.3 mph (nearest tenth)
Not:
The direction of the plane is
tan⁻¹ 23/200 = 6.56° west of north.
Answer:
The 4th graph
Step-by-step explanation:
To have a maximum value, your parabola would have to open downwards. So the first 2 are wrong. Since your y-intercept is positive 4, your graph would have to touch the y axis at 4. The 3rd graph is wrong since it touches the y-axis at a negative point. The correct answer would be the 4th answer choice.
50 + x ≥ 268
X ≥ 218
STEP BY STEP WORK
50 + x ≥268
-50 -50
x ≥218
Jan needs to save at least $218 for camp
Hope I helped :)
So 7 is greater I am not smart I am just trying to answers some question
