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konstantin123 [22]
4 years ago
6

What is the value of X?

Mathematics
1 answer:
r-ruslan [8.4K]4 years ago
8 0
Divide 129.2 and 57mm
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Find elapsed time between 7:10 am to 8:15am two way
Marianna [84]
First Way:
7: 10am to 8:00am = 50 mins
8:00am to 8:15am = 15 mins
Total = 50 min + 15 min = 65 mins = 1 hour 5 mins

Second Way:
7: 10am to 8:10am = 1 hour
8:10am to 8:15am = 5 mins
Total = 1 hour + 5 mins = 1 hour 5 mins

Answer : 1 hour 5 mins
7 0
3 years ago
Read 2 more answers
Plz help! Is this right? Question is below!
GalinKa [24]

Answer:

infinitely many solutions

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
PLEASE GUYS HELP ME I NEED THIS FOR A TEST NOW
ValentinkaMS [17]

Answer:

23.54 m

Step-by-step explanation:

Applying

cos∅ = adjacent(A)/hypotenuse(H)

cos∅ = A/H................ Equation 1

make H the subject of the equation

H = A/cos∅............ Equation 2

Given: A = 15 m, ∅ = 25°

Substitute into equation 2

H = 15/cos25

H = 16.55 m

Also,

tan∅ = opposite(O)/Adjacent(A)

tan∅ = O/A............Equation 3

Make O the subject of the equation

O = Atan∅.......... Equation 4

Substituting into equation 4

O = 15(tan25°)

O = 6.99 m.

From the diagram,

The height of the goal post before snap = H+O

The height of the goal post before snap = 16.55+6.99

The height of the goal post before snap = 23.54 m

4 0
3 years ago
Find a vector equation and parametric equations for the line. (Use the parameter t.) The line through the point (0, 11, −8) and
NNADVOKAT [17]

Answer:

The vector equation of the line is \overrightarrow {r}=(11j-8k)+t(4i-4j+6k) and parametric equations for the line are x=4t, y=11-4t, z=-8+6t.

Step-by-step explanation:

It is given that the line passes through the point (0,11,-8) and parallel to the line

x=-1+4t

y=6-4t

z=3+6t

The parametric equation are defined as

x=x_1+at,y=y_1+bt,z=z_1+ct

Where, (x₁,y₁,z₁) is point from which line passes through and <a,b,c> is cosine of parallel vector.

From the given parametric equation it is clear that the line passes through the point (-1,6,3) and parallel vector is <4,-4,6>.

The required line is passes through the point (0,11,-8) and parallel vector is <4,-4,6>. So, the parametric equations for the line are

x=4t

y=11-4t

z=-8+6t

Vector equation of a line is

\overrightarrow {r}=\overrightarrow {r_0}+t\overrightarrow {v}

where, \overrightarrow {r_0} is a position vector and \overrightarrow {v} is cosine of parallel vector.

\overrightarrow {r}=(11j-8k)+t(4i-4j+6k)

Therefore the vector equation of the line is \overrightarrow {r}=(11j-8k)+t(4i-4j+6k) and parametric equations for the line are x=4t, y=11-4t, z=-8+6t.

3 0
3 years ago
1/2x2 pints = what please answer the question right away
DENIUS [597]

Answer: 1 pint

Step-by-step explanation:

half a pint times 2 is just half a pint plus half a pint. half of one plus half of one is one whole so its 1 pint

7 0
3 years ago
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