The distance of the ball from the foot of the tower is : 35.18m
The ball would be moved 57.2m away from the foot of the tower for the Angle of elevation to be halved.
<h3>What is angle of elevation?</h3>
Angle of elevation is the angle formed between the horizontal and the line of view from the vertical.
Analysis:
The height of the tower and the distance of the ball from the foot of the tower form a right angle triangle.
so we use trigonometry.
a) let distance of the ball from foot of tower be x.
so that, tan 52 = 45/x
x = 45/tan52
x = 45/1.279 = 35.18m
b) let the distance of the ball in the new position from the foot of the tower be y.
if the angle of elevation is halved, then new angle is 52/2 = 26°
tan 26 = 45/y
y = 45/tan26 = 45/0.487 = 92.4m
distance moved from old position to new position = 92.4 - 35.18 = 57.2m
In conclusion, the distance of the ball from the foot of the tower and the distance the ball should move to make its elevation 26° are 35.18m and 57.2m respectively.
Learn more about angle of elevation: brainly.com/question/88158
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An ordered pair is written like this, ( x, y ). In this case x = 0 and y = -3. On a graph the vertical line is the y-axis and the horizontal line is the x-axis. The origin is point ( 0, 0 ). To the left of the origin on the x-axis is the negative number line and to the right is the positive number line. On the y-axis, south of the origin is the negative number line and north is the positive number line. When you plot a point on a graph you do x first, so if x equals 1, you would move one right, -1, one left. IF y were to equal 2 then from the place where you are on the x-axis, 1, you would move two up, -2, two down. In this case x = 0 so you would stay at the origin, and y = -3 so you would move 3 down. So ( 0, -3 ) would lie negative y-axis. The answer is D.
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
x= 1, y= -4
Answer:
(1/4)*(e⁶ - 7)
Step-by-step explanation:
a) Given
x − y = 0 if x = 0 ⇒ y = 0
x − y = 2 if x = 0 ⇒ y = -2; if y = 0 ⇒ x = 2
x + y = 0 if x = 0 ⇒ y = 0
x + y = 3 if x = 0 ⇒ y = 3; if y = 0 ⇒ x = 3
then we show the region R in the pics 1 and 2.
b) We make the change of variables as follows
u = x + y
v= x - y
If
x - y = 0 ⇒ v = 0
x − y = 2 ⇒ v = 2
x + y = 0 ⇒ u = 0
x + y = 3 ⇒ u = 3
Where u is the horizontal axis and v is the vertical axis, the new region S is shown in the pic 3.
c) We evaluate ∫∫R (x + y)*e∧(x² - y²)dA
The procedure is shown in the pic 4, where we have to calculate the Jacobian in order to use it to get the answer.
In an isosceles triangle, there are two sides that are congruent.
In this case, AB and BC are congruent.
Knowing this, we know that AB = BC
Since we know the values of AB and BC, we can put them into the equation:
3x - 4 = 5x - 10
Subtract 3x from both sides:
-4 = 2x - 10
Add 10 to both sides to isolate 'x':
6 = 2x
Divide both sides by 2:
x = 3
Now that we know the value of the variable, we just have to input it into AB's equation:
3x - 4 = 3(3) - 4
3(3) - 4 = 9 - 4
9 - 4 = 5
<u>AB = 5</u>
Good luck!
