Answer:
Let,
P= kT
P = 10, when T = 500
So, 10=k500
or, k=10/500
or, k=1/50
When T=509
P=kT
or, P=(1/50)×509
or, P=508/50
or, P = 10.18
And when P = 509 (since the question isn't clear)
509=(1/50)×T
or, T=509×50
or, T=25450
86/139*100%= 61.87%
The final answer is 61.87%~
2 lines intersect at (1,2)
so answer is Yes.
(1,2) is the solution to the system.
<u>Answer-</u>
<em>Perimeter of the kite is </em><em>16.2 units</em>
<u>Solution-</u>
As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY
So, perimeter of the kite WXYZ is,

And


So, perimeter will be,

f(x) as a linear equation:
gradient = (12-4)/(4-2) = 4
y - 4 = 4(x - 2)
y = 4x - 4
Therefore f(x) = 4x - 4
g(x) = 10x - 4
Since it already started at 10 and it increases by one every level (x):
h(x) = x + 10
Therefore, since g(x) has the largest gradient (10x), it has the largest slope