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olga2289 [7]
3 years ago
13

What are the y-intercept and the slope of the graph of the following equation? -2×+y=8

Mathematics
1 answer:
masha68 [24]3 years ago
3 0

Y intercept is 8

Slope is 2

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What is the factored form of the expression t^2-25
LekaFEV [45]
This is called difference of squares. It's like 
a^2-b^2=(a-b)(a+b)

t^2-25=(t-5)(t+5)

Hope this helps :)
3 0
3 years ago
A single-server waiting line system has an arrival pattern characterized by a Poisson distribution with 3 customers per hour. Th
sweet-ann [11.9K]

Answer:

18 minutes

Step-by-step explanation:

Given that:

The arrival time = 3 customers / hour

The avg. service rate (s) = 12 minutes per customer

To hour, we have:

s = \dfrac{60}{12}

s = 5 customers/ hour

Thus, the required average time for a customer needs to wait in line is:

= \dfrac{3}{5}\times (5-3) hours \\ \\ = \dfrac{3}{5}\times 2 \\ \\ = \dfrac{3}{10} \ hours

To minutes;

= 3 \times \dfrac{60}{10} \ minutes

= 18 minutes

3 0
3 years ago
Find the value of x<br><br>60 <br>58<br>64<br>62​
monitta

Answer:

64

Step-by-step explanation:

The interior angle of a circle has the theorem divide in 2 the sum of the arcs on the circle.

The circle has arcs 42 and 86.

The interior angle is 42 + 86 = 128.

128/2 = 64

4 0
4 years ago
Hewo Pls Answer the questions below TY!
Musya8 [376]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
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