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irina1246 [14]
3 years ago
12

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p

ower?
Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

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worty [1.4K]

Answer:

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Step-by-step explanation:

Given that a shuttle launch depends on three key devices that may fail independently of each other with probabilities 0.01, 0.02, and 0.02, respectively.

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Since each key device is independent of the other

we have

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3 years ago
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Answer:

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The price of a package of gingerbread is $17.18

Step-by-step explanation:

11x + 12y = 352

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Let "x" be the price of a package of chocolate chip.

Let "y" be the price of a package of gingerbread.

11x + 12y = 352(Multiply the 1st row by 10)

10x +8y = 270 (Multiply the 2nd row by 11)

-------------------

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--------------------------

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110x + 120y = 3520

110x+ 120(17.1875)= 3520

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Answer:

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