If a beam can hold 2,000 pounds at 15 feet, what is the safe load if the length of the beam is 10 feet?

Mathematics

2 answers:

denis23 [38]3 years ago

6 0

Answer: The correct answer is 3,000

Komok [63]3 years ago

3 0

Let's see how many pounds can a one foot I-beam handle. If a 15 feet I-beam can handle 2000 pounds, then a one foot I-beam can handle 1/15 of that weight.

2000 * $\frac{1}{15}$ = 133 1/3

So, for every extra foot, it can handle an additional 133 1/3 pounds.

Now we want to find out how many pounds a 10 feet I-beam can handle.

10 * $\frac{400}{3}$ = 4000/3 or 1333 1/3 pounds

So, a 10 feet I-beam can handle 1333 1/3 pounds.

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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

Given that:

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the area of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

3 years ago

How could i figure this out?

Black_prince [1.1K]

16 fluid ounces = 1 pint

so to find how many 1 pint containers you need to divide :

32 fluid ounces ÷ 16 fluid ounces = 2 pints

hope this made sense

7 0

3 years ago

Read 2 more answers

PLS HELP ME WITH 3! THANK YIU SO MUCH!! (Random answers gets moderated.)

kirill115 [55]