Answer: 3.61×10^5 A
Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.
The formulae is given below as
B = u×Ia²/2(x²+a²)^3/2
Where B = strength of magnetic field on the axis of a circular loop = 4.15T
u = permeability of free space = 1.256×10^-6 mkg/s²A²
I = current on loop =?
a = radius of loop.
Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m
x = distance of the sensor away from center of loop = 2.10 cm = 0.021m
By substituting the parameters into the formulae, we have that
4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2
4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2
4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)
4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I
I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9
I = 4.80×10^-4 / 1.32665 ×10^-9
I = 3.61×10^5 A
Answer:
• x = 9
• y = 6√2
Step-by-step explanation:
The right triangles are all similar, so the ratios of hypotenuse to short side are the same:
27/x = x/3
x^2 = 81 . . . . . multiply by 3x
x = 9 . . . . . . . . take the square root
Then y can be found from the Pythagorean theorem:
x^2 = y^2 + 3^2
81 - 9 = y^2 = 72 . . . . . subtract 9
y = √72 = 6√2 . . . . . . .take the square root
The values of x and y are 9 and 6√2, respectively.
Answer:
the first option - 48s + 4.75
Step-by-step explanation:
Answer:
A.
<u>The first 5 terms:</u>
- a₁ = (2*1 + 3) / 4 = 5/4
- a₂ = (2*2 + 3) / 4 = 7/4
- a₃ = (2*3 + 3)/ 4 = 9/4
- a₄ = (2*4 + 3) / 4 = 11/4
- a₅ = (2*5 + 3) / 4 = 13/4
B.
<u>The first 5 terms:</u>
- a₁ = (1 - 3) / (1 - 2) = 2
- a₂ = (2 - 3) / (2 - 2) = undefined
- a₃ = (3 - 3)/ (3 - 2) = 0
- a₄ = (4 - 3) / (4 - 2) = 1 / 2
- a₅ = (5 - 3) / (5 - 2) = 2 / 3
= 133 1/3
= 4000/3 or 1333 1/3 pounds