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3 years ago

If a beam can hold 2,000 pounds at 15 feet, what is the safe load if the length of the beam is 10 feet?

Mathematics

2 answers:

denis23 [38]3 years ago

6 0

Answer: The correct answer is 3,000

Komok [63]3 years ago

3 0

Let's see how many pounds can a one foot I-beam handle. If a 15 feet I-beam can handle 2000 pounds, then a one foot I-beam can handle 1/15 of that weight.

2000 * $\frac{1}{15}$ = 133 1/3

So, for every extra foot, it can handle an additional 133 1/3 pounds.

Now we want to find out how many pounds a 10 feet I-beam can handle.

10 * $\frac{400}{3}$ = 4000/3 or 1333 1/3 pounds

So, a 10 feet I-beam can handle 1333 1/3 pounds.

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The perimeter of a rectangular baking sheet is 58 inches and its area is 201.25 in.2. What are the length and width of the bakin

anzhelika [568]

Answer:

$Length=17.5\ in\\\\Width=11.5\ in$

Step-by-step explanation:

The formula for calculate the Area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

And the formula for calculate the peimeter of a rectangle is:

$P=2l+2w$

Where "l" is the lenght and "w" is the width.

We know that the perimeter of the rectangular baking sheet is 58 inches and its area is 201.25 in². Then:

$A=201.25\ in^2\\\\P=58\ in$

<u>The steps are:</u>

1. Solve for the "l" from the formula $A=lw$ :

$A=lw\\\\l=\frac{A}{w}\\\\\l=\frac{201.25}{w}$

2. Substitute $l=\frac{201.25}{w}$ into the formula $P=2l+2w$ and solve for "w":

$58=2(\frac{201.25}{w})+2w\\\\58=\frac{402.5}{w}+2w\\\\58=\frac{402.5+2w^2}{w}\\\\58w=402.5+2w^2\\\\2w^2-58w+402.5=0$

Applying the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$ , we get:

$x=w=\frac{-(-58)\±\sqrt{(-58)^2-4(2)(402.5)}}{2(2)}\\\\w_1=17.5\\\\w_2=11.5$

3. Substitute $w_1=17.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{17.5}=11.5$

4. Substitute $w_2=11.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{11.5}=17.5$

Therefore, since the value of the lenght of a rectangle must be greater that the value of the width, we can conclude that the lenght and the width of the rectangular baking sheet are:

$l=17.5\ in\\\\w=11.5\ in$

8 0

3 years ago

If a soccer team played 160 games and won 65% of them, how many games did they win?

Sindrei [870]

The correct answer is 104 games.

You get that number by dividing 160 with a 100, to find out how large 1% is, and then you multiply it with 65 to find out how much 65% is, and the answer is 104 games.

4 0

3 years ago

How many meters are the<br>Convert 5.2kg to grams.<br>

Misha Larkins [42]

Answer:

5.2kg = 5,200 grams

Step-by-step explanation:

I hope it helps

6 0

2 years ago

What is the probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator

kirill [66]

Answer:

See explanation

Step-by-step explanation:

Total number of letters = n! = 10

Permutation for 10 letters = n!

= 10!

= 10*9*8*7*6*5*4*3*2*1

= 3628800

From n letters:

Number of A = 2

Number of C = 2

Number of L = 2

A₁, A₂, C₁, C₂, L₁, L₂, O, R, T, U

Out of 3628800 permutations the word calculator can be spelled as:

C₁ A₁ L₁ C₂ U L₂ A₂ T O R

C₂ A₂ L₂ C₁ U L₁ A₁ T O R

and so on

So total number of different permutations are

(permutation of number of letters) / permutation of (number of As * number of Cs * number of Ls)

= 10! / (2! 2! 2 !)

= 10*9*8*7*6*5*4*3*2*1 / (2*1) (2*1) (2*1)

= 3628800 / 2 * 2 * 2

= 3628800 / 8

= 453600

Hence probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator" is:

1 / total number of different permutations

= 1 / 10! / (2! 2! 2 !)

= 1/453600

= 0.000002

8 0

3 years ago

Can someone help me with these

vampirchik [111]

Answer: x-intercept is -9

Step-by-step explanation: To find the x intercept y is 0 and to find the y intercept x is 0. 18 divided by -2 is -9, which is the answer

3 0

3 years ago