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Angelina_Jolie [31]
3 years ago
8

*MAKE SURE YOUR ANSWER IS CORRECT* // *NEED HELP* Spinner A and Spinner B have 5 color choices each: red, yellow, blue, green an

d pink. What is the probability of getting a green and pink combination from the area model?

Mathematics
1 answer:
qaws [65]3 years ago
6 0

Answer:

P = 2 / 25

Step-by-step explanation:

If we assume that the combination of green and pink means, 1 green and 1 pink, then we can say the following:

P = 1 / 25 + 1 / 25

P = 2 / 25

This is because the squares where green and pink intersect only occurs twice.

Hence, the probability is P = 2 / 25.

Cheers.

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Determine the relationship between the two triangles and whether or not they can be proven to be congruent.​
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Answer:

- ASA stands for "angle, side, angle" and means that we have two triangles where we know two angles and the included side are equal.

- If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

Step-by-step explanation:

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3 years ago
Which would be the farthest from 0<br> 20, -21, -20.5, or 21.5
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21.5 is because it’s counting the same from 0 and 21.5 is the highest number
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AND<br> - 4x + 3 &lt; -6<br> 12.c<br> · 39 &lt; 9
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3 0
3 years ago
An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

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