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Harrizon [31]
2 years ago
12

Given: 1/3 x+y= 15.

Mathematics
1 answer:
storchak [24]2 years ago
6 0

Answer:

B) [(-3, 16), (0, 15), (3, 14)]

Step-by-step explanation:

Because 1/3(-3)+16=-1+16=15,

1/3(0)+15=0+15=15,

1/3(3)+y=1+14=15.

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oksian1 [2.3K]
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                    =  \frac{55}{6}
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7 0
3 years ago
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F(x) = 7|x| awnser the question for some points
Eddi Din [679]

f(x) = 7|x|

if x= 1

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5 0
2 years ago
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18x (14 - 9) ÷[12 - (19 - 13)] = what is the answer​
marysya [2.9K]

Answer:

15

Step-by-step explanation:

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18 . ( 5 ) ÷ [ 12 - 6 ]

90 ÷ 6

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5 0
2 years ago
The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c
valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is 10.4 \:cm^2

Step-by-step explanation:

The area of a rectangle with length L and width W is A= L\cdot W so the differential of <em>A</em> is

dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W

\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L so

dA=W\Delta L+L \Delta W

We know that each error is at most 0.1 cm, we have |\Delta L|\leq 0.1, |\Delta W|\leq 0.1. To find the maximum error in the calculated area of the rectangle we take \Delta L = 0.1, \Delta W = 0.1 and L=55, W=49. This gives

dA=49\cdot 0.1+55 \cdot 0.1

dA=10.4

Thus the maximum error in the calculated area of the rectangle is 10.4 \:cm^2

4 0
3 years ago
Type the correct number in the blank
Mademuasel [1]

Answer:

4.11

Step-by-step explanation:

7 0
2 years ago
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