Question

What is the perimeter of abc Round each step to the nearest tenth.

Answer 1

The perimeter is 15.833 which would be 15.8 rounded. I am not 100% sure but hope it helps.

Answer 2

For this case, we have that the perimeter of the triangle will be given by the sum of its sides.

To find the measure of each side, we apply the formula of the distance between two points:

$d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}$

AB side:

$AB = \sqrt {(- 1-5) ^ 2 + (1 - (- 1)) ^ 2}\\AB = \sqrt {(- 6) ^ 2 + (2) ^ 2}\\AB = \sqrt {36 + 4}\\AB = \sqrt {40}\\AB = 6.3$

BC side:

$BC = \sqrt {(0 - (- 1)) ^ 2 + (- 3-1) ^ 2}\\BC = \sqrt {(1) ^ 2 + (- 4) ^ 2}\\BC = \sqrt {1 + 16}\\BC = \sqrt {17}\\BC = 4.1$

CA side:

$CA = \sqrt {(5-0) ^ 2 + (- 1 - (- 3)) ^ 2}\\CA = \sqrt {(5) ^ 2 + (2) ^ 2}\\CA = \sqrt {25 + 4}\\CA = \sqrt {29}\\CA = 5.4$

Thus, the perimeter of the figure is: 15.8

ANswer:

15.8