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3 years ago

Find the values for a and b that would make the following equation true (ax^2)(-6x^b)=12x^5

Mathematics

1 answer:

dedylja [7]3 years ago

3 0

Answer:

x^b=x^3

Step-by-step explanation:

(ax^2)(-6x^b)=12x^5

(a)(6)=6a or a6

(x^2)(x^b)=x^5

x^3 because

(a^b)(a^c)=a^b+c

Hope this helped.

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3 years ago

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Georgia [21]

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4 years ago

Is 6+2 +4x equivalent to 6- ( 2-4x) . if not , why not ?

Xelga [282]

Well lets solve for both.
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3 years ago

Let’s assume that human body temperatures are normally distributed with a mean of 98.20° F and a standard deviation of 0.62° F.

uysha [10]

Answer: It is such a small percentage of the population that would be considered to have fever at that level.

So, it is not appropriate stringent standard.

Step-by-step explanation:

Since we have given that

Mean = 98.20°F

Standard deviation = 0.62°F

If Bellevue Hospital in New York City uses 100.6°F as the lowest temperature considered to be a fever.

So, $\bar{X}=100.6^\circ F$

So, using the normal distribution, we first find the value of z.

$z=\dfrac{\bar{x}-\mu}{\sigma}\\\\x=\dfrac{100.6-98.2}{0.62}\\\\z=3.87$

Since z = 3.87

So, p = 0.0001 =0.1%

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3 years ago

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Digiron [165]

Answer: 4/18

Step-by-step explanation:

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3 years ago