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3 years ago

Find the values for a and b that would make the following equation true (ax^2)(-6x^b)=12x^5

Mathematics

1 answer:

dedylja [7]3 years ago

3 0

Answer:

x^b=x^3

Step-by-step explanation:

(ax^2)(-6x^b)=12x^5

(a)(6)=6a or a6

(x^2)(x^b)=x^5

x^3 because

(a^b)(a^c)=a^b+c

Hope this helped.

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Please help with right answers xoxo

ludmilkaskok [199]

Y = 3x - 4

y = 3(-1) - 4
y = -3 - 4 = -7
Graph pair is (-1, -7)

y = 3(0) - 4
y = 0 - 4 = -4
Graph pair is (0, -4)

y = 3(2) - 4
y = 6 - 4 = 2
Graph pair is (2, 2)

y = 3(4) - 4
y = 12 - 4 = 8
Graph pair is (4, 8)

6 0

3 years ago

40 is 20% of x. If x is 80% of y, then what is the sum of x and y?

Tanzania [10]

40 is 20% of x

40 = .2 * x

40/.2 = x

x =200

x is 80% of y

x = .8 * y

200 = .8 *y

200/.8 = y

250 =y

x+y

200+250

450

5 0

3 years ago

The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa

horsena [70]

Answer:

7.2 years

Step-by-step explanation:

$f(t) =200(1 - 0.956e^{-0.18t})$

where f(t) is the length and t is the number of years old

given the Mike measures 148 cm, we need to find out the age

So we plug in 148 for f(t) and solve for t

$148 =200(1 - 0.956e^{-0.18t})$

divide both sides by 200

$\frac{148}{200} = 1 - 0.956e^{-0.18t}$

Now subtract 1 from both sides

$-0.26= - 0.956e^{-0.18t}$

Divide both sides by -0.956

$\frac{0.26}{0.956} =e^{-0.18t}$

Now take ln on both sides

$\frac{0.26}{0.956} =e^{-0.18t}$

$ln(\frac{0.26}{0.956} )=-0.18tln(e)$

$ln(\frac{0.26}{0.956} )=-0.18t$

divide both sides by -0.18

t=7.2

So 7.2 years

5 0

3 years ago

5x5=25 i did the quiz and got it right

Sedaia [141]

Congratsss good jobbb

5 0

2 years ago

Read 2 more answers

Solve 4 + 2 sinx= 14-8 sinx for 0° ≤ x ≤ 180

Oduvanchick [21]

<h2>Answer:</h2>

<u>x= 90°</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expression.</h3>

$4 + 2 sin(x)= 14-8 sin(x)$

<h3>2. Subtract "4" from both sides of the equation.</h3>

$-4+4 + 2 sin(x)= 14-8 sin(x)-4\\ \\2 sin(x)= 10-8 sin(x)$

<h3>3. Add "8sin(x)" to both sides of the equation.</h3>

$2 sin(x)+8 sin(x)= 10-8 sin(x)+8 sin(x)\\ \\10 sin(x)= 10$

<h3>4. Divide both sides by 10.</h3>

$\frac{10 sin(x)}{10} = \frac{10}{10} \\ \\sin(x)=1$

<h3>5. Apply the arcsin of sin^-1 to both sides of the equation.</h3>

$arcsin(sin(x))=arcsin(1)\\ \\x=90$

<h3>6. Conclude.</h3>

<u>x= 90°</u>.

3 0

1 year ago