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masya89 [10]
3 years ago
14

What information cannot be determined from the general linear equation, y = bx + a?

Mathematics
2 answers:
Tresset [83]3 years ago
6 0
This is pretty easy but what cannot be determined is the correlation between x and y :).

Hope this helps!
gulaghasi [49]3 years ago
3 0
The center point and endpoints cannot be determined.
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Write an equation of the line passing through the point (7, 3) that is parallel to the line 4x - 7y=9
lina2011 [118]

Answer:

y = 4/7x - 1

Step-by-step explanation:

7y = 4x - 9

y = 4/7x - 9/7

3 = 4/7(7) + b

3 = 4 + b

b = -1

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Naddik [55]
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If a line of one billion people standing shoulder to shoulder stretches 395815 miles long what is the average shoulder width in
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3 years ago
A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical​ (ha
Neko [114]

Answer:

Volume: \frac{2}{3}\pi r^3

Ratio: \frac{2}{9}r

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

V=\frac{4}{3}\pi r^3

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

A=4 \pi r^2

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so 2\pi r^2. Moreover, we have to add the surface of the base, which is \pi r^2. So the total surface area of the hemispherical tank is

A'=2\pi r^2 + \pi r^2 = 3 \pi r^2

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r

6 0
3 years ago
Find the slope (3, 4) and (-5, 0)
inn [45]

Answer:

1/2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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