Answer:
3. 150.72 in²
4. 535.2cm²
Step-by-step Explanation:
3. The solid formed by the net given in problem 3 is the net of a cylinder.
The cylinder bases are the 2 circles, while the curved surface of the cylinder is the rectangle.
The surface area = Area of the 2 circles + area of the rectangle
Take π as 3.14
radius of circle = ½ of 4 = 2 in
Area of the 2 circles = 2(πr²) = 2*3.14*2²
Area of the 2 circles = 25.12 in²
Area of the rectangle = L*W
width is given as 10 in.
Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in
Area of rectangle = L*W = 12.56*10 = 125.6 in²
Surface area of net = Area of the 2 circles + area of the rectangle
= 25.12 + 125.6 = 150.72 in²
4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)
=
Where,
b = 8 cm
h =
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Answer:
B.
Step-by-step explanation:
When reflecting over the x-axis:
(x, y) (x, -y)
The y changes signs (+, -)
They are based on SSS. They have the middle side which they share and is equal. And those other two lines also make those sides equal, so all sides are equal and they’re congruent
<span>The part of the graph that best represents the solution set to the system of inequalities y ≤ x + 1 and y + x ≤ –1 is Part C.</span>