The solutions to the inequalities are x >1 and x < 6
<h3>How to solve the inequalities?</h3>
The inequality expression is given as:
-2x + 5 < 3x + 10
Collect the like terms in the above inequality
-2x - 3x < 10 - 5
Evaluate the like terms
-5x < 5
Divide by -5
x >1
Also, we have
5(x - 2) <3x + 2
Open the bracket
5x - 10 < 3x + 2
Evaluate the like terms
2x < 12
Divide by 2
x < 6
Hence, the solutions to the inequalities are x >1 and x < 6
Read more about inequalities at
brainly.com/question/24372553
#SPJ1
Hello! I can help you with this!
4.
a. $100
b. $360
The formula to find the answers to these kinds of problems is p * r * t. The rate is always a decimal, so if the rate is 8%, you multiply by 0.08. If the rate is 12%, you multiply by 0.12, and so on.
5.
a. 12.8
b. 31 1/6
I got these answers by doing the distributive property. Replace each variable with the number it represents, multiply each by two and add them up to get these answers. For the fraction one, you can set up each fraction by finding the LCD before multiplying by 2, or you can find a fraction calculator online and add the numbers up.
6.
a. x = 20
b. x = 3
c. x = 13
d. x = 0
e. x = 4
f. x = 7
g. x = -3
I solved this problem by doing the distributive property and doing these kinds of problems step by step. It’s long to explain, but hopefully your teacher has good notes for you to look back on over these types of questions. If there is only a negative sign in front of the distributive property equation, then you basically distribute -1 to each number. In these long equations, combine like terms. You must do these kinds of questions right, because it’s easy to mess up and get wrong answers if you don’t do the right steps in order.
5y - 2x + 1 = 0.
5y = 2x-1.
y = 2/5 x - 2/5
this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)
tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2
M(Slope)= -3/-5x
B(Y-Intercept)=-5
Mx+b(Equation)=-3/-5x-5
1 meter = 100 centimeters
16*100 = 1600 cm
1600/70 = 22.86
The largest number of fence posts that can be possibly cut from the log is 22.