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Mama L [17]
3 years ago
11

A company needs to hire a new director of advertising. It has decided to try to hire person A or B, who are assistant advertisin

g directors for its major competitor. To decide between A or B, the company finds that A is in charge of 2/3 of the total accounts while Peron B is in charge of only 1/3 of the accounts. Also, A’s campaigns have satisfactory results 3 out of 4 times, while B’s campaigns has satisfactory results only 2 out of 5 times. Suppose one of the competitors ad campaigns is selected randomly
a) Draw the tree diagram of the info above
b) Find the probability that A is in charge of the selected campaign and that is produces satisfactory results
c) Find the probability that the selected campaign is satisfactory
Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

b) 0.5

c) 0.633

Step-by-step explanation:

a) Please find the attached image - tree diagram

b) b) The probability that A is in charge of the selected campaign and that it produces satisfactory results  = 2/3 * 3/4 = 1/2 = 0.5

c) P (selected campaign is satisfactory)

         = P(A's campaign and satisfactory) + P(B's campaign and satisfactory)

         = 2/3*3/4 + 1/3*2/5

         = 0.6333

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Sholpan [36]

Answer:

A. {(5, –4), (–4, 5), (–5, 4), (4, –5)}

Step-by-step explanation:

Since there is one value of  

y

for every value of  

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in  

(

5

,

−

4

)

,

(

−

4

,

5

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,

(

−

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(

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, this relation is a function.

The relation is a function.

5 0
3 years ago
Atrain leaves a station and travels north at 50 kmh Four hours later a second train leaves on a paralel track and travels north
ryzh [129]

Answer:

Step-by-step explanation:

50 X 4= 200

90 X 5=450

50 X 5=250

200 + 250 = 450

Therefore it takes 5 hours for train B which is the train moving at 90 km per hr  to catch up to train A.

3 0
3 years ago
Help!! algebra two!! <br> c-h :)
kotegsom [21]

Answer:

c. (2x + 3y)² = (2x)² + 2(2x)(3y) + (<u>3y</u>)²

d. (w - 1)(1 + w + w²) = <u> </u><u>w³</u> - 1

e. a² - 16 = (a + <u>4</u>)(a - <u>4</u>)

f. (2x + 5y)(2x - 5y) = <u>4x²</u> - <u>25y²</u>

g. (2²¹ - 1)(2²¹ + 1) = <u>2⁴²</u> - 1

h. [(x - y) - 3][(x - y) + 3] = (<u>x - y</u>)² - 9

Step-by-step explanation:

c. Although this expression, when squared, is really <em>4x</em><em>²</em><em> </em><em>+</em><em> </em><em>12xy</em><em> </em><em>+</em><em> </em><em>9y</em><em>²,</em><em> </em>they just splitted it up into several more terms. In this last blank should be a 9y², but instead, they took the square root of the term, which is <em>3y,</em><em> </em>and set the square outside of the parentheses.

*I bet that was what made it confusing, but have no fear. The mathematics tutor is here.

d. This is similar to the Quadratic Equation [<em>y</em><em> </em><em>=</em><em> </em><em>Ax</em><em>²</em><em> </em><em>+</em><em> </em><em>Bx</em><em> </em><em>+</em><em> </em><em>C</em>] where you can, what I like to call... FOIL it, however, you have an extended amount of terms. Although you still have to FOIL it, it is just a unique procedure. This time, you have to one-by-one, take each term in the first set of parentheses [-1 and w] and multiply them by the second all three terms in the second set of parentheses.

e. This is a piece of cake because we know BOTH square roots of 16 and we are multiplying what are called conjugates.

f. Again, we are multiplying conjugates, so we just multiply the first and last two terms in each set of parentheses.

g. Again, we are multiplying conjugates EXCEPT now, we have exponents in each set of parentheses. Whenever you multiply terms, you add the exponents and your base remains the same, which is what you see in the above answer.

h. For the final exercise, we are multiplying conjugates again, and we obviously can see what fills that blank because there are TWO IDENTICAL EXPRESSIONS that are being multiplied, which in this case are being "squared", and that expression is <em>x</em><em> </em><em>-</em><em> </em><em>y</em><em>.</em><em> </em>It appears twice, so that is a giveaway.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**Conjugates are IDENTICAL expressions with OPPOSITE operation symbols. Whenever you multiply conjugates, just add the first and last two terms in both sets of parentheses because when you FOIL, the midst term will ALWAYS result in zero.

8 0
4 years ago
Find (f - g)(x) if f(x) = x2 ­- x - 6 and g(x) = 2x2 - 3x + 4
Nadya [2.5K]
For this question we just have to re-substitute the expressions for their respective functions by assigning them in a plausible condition for two functions. Here, the first function of "x" is subtracted by a second function of "x". The expressions are assigned according to the first and second function expressions in each case or condition.

All we have to do is distribute the parentheses for second expression to deploy positive addition between 2x^2 and 3x. Furthermore grouping all the like terms to get the required answer to this query. So, let me express this via LaTeX interpreter equation editor for a better understanding and clear all the doubts for these forms of queries.

\mathbf{Since, \: \: f(x) = x^2 - x - 6}

\mathbf{\therefore \quad \Big(x^2 - x - 6 - g(x) \Big) \: (x)}

\mathbf{Since, \: \: g(x) = 2x^2 - 3x + 4}

\mathbf{\therefore \quad x^2 - x - 6 - (2x^2 - 3x + 4)}

\mathbf{x^2 - x - 6 - (2x^2) - (- 3x) - (+ 4)}

\mathbf{x^2 - x - 6 - 2x^2 + 3x - 4}

\mathbf{x^2 - 2x^2 - x + 3x - 6 - 4}

\mathbf{x^2 - 2x^2 + 2x - 6 - 4}

\mathbf{- x^2 + 2x - 6 - 4}

\boxed{\mathbf{\underline{Required \: \: Answer: \: - x^2 + 2x - 10}}}

Hope it helps.
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3 years ago
872x3 estimated problem
denis23 [38]
872 times 3=2616, just try to use a Calculator if you can
4 0
3 years ago
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