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julia-pushkina [17]
3 years ago
15

Los dueños de un restaurante cultivan sus propios

Mathematics
1 answer:
hammer [34]3 years ago
7 0

Answer:

Quedan 2.083 m^3 de agua en el reservorio.

Equivalen a 2083 litros.

Step-by-step explanation:

Los dueños del restaurante tienen un reservorio de agua cuyo volumen es de 6.25 m^3.

Si han utilizado 2/3 del reservorio, esto implica que aún quedan en el reservorio una tercera parte del volumen original (1/3).

Entonces, la cantidad de metros cúbicos (m^3) de agua que quedan en el reservorio se puede calcular como:

V=(1/3)\cdot V_0=(1/3)\cdot6.25\,m^3=2.083\,m^3

Este valor equivale a un volumen en litros de:

V=2.083\,m^3\cdot \dfrac{1,000\,l}{1m^3}=2,083\,l

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alukav5142 [94]

Answer:

1=3 given

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2=4 transitive property (?)

Step-by-step explanation:

it's been a while since i've done proofs but i think this is right

4 0
2 years ago
4. Ketisha is practicing for a marathon by running around a track that is 440 yards long. Yesterday she ran around the track 20
adoni [48]
440 yards x 20 = 8800 yards.

8800 yards is equal to 5 miles.
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3 years ago
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notsponge [240]
Line a and b are perpendicular
3 0
3 years ago
ONLY ANSWER THIS IF YOU HAVE AN EXPLANATION AND IF YOU KNOW WHAT THE ANSWER IS.
Bad White [126]
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6 0
3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a
VMariaS [17]
(a) If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) e^{kt}=100e^{kt}.

y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\
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(b) y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}

(c)
100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\
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3 0
3 years ago
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