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3 years ago

PLEASE HELP ME IM OFF PACE

Mathematics

2 answers:

Yuki888 [10]3 years ago

8 0

Estimate higher Might Be It

denpristay [2]3 years ago

7 0

select the one that says "no, the estimate should be higher."

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Brian cut a piece of cardboard in the shape of a trapezoid the area of the cut out is 43.5 cm² if the bases are 6 cm And 8.5 cm

Likurg_2 [28]

Answer: the height of the trapezoid is 6 cm

Step-by-step explanation:

The formula for determining the area of a trapezoid is expressed as

Area = 1/2(a + b)h

Where

a and b are the length of The bases are the 2 sides of the trapezoid which are parallel with one another.

h represents the height of the trapezoid.

From the information given,

a = 6 cm

b = 8.5 cm

If the area of the cut out is 43.5 cm², then

53.5 = 1/2(6 + 8.5)h

Cross multiplying by 2, it becomes

43.5 × 2 = (6 + 8.5)h

87 = 14.5h

h = 87/14.5 = 6 cm

8 0

3 years ago

Write an expression that equals 56. Include an exponent.

Troyanec [42]

There are many possibilities. An example is $1^{1} + 55 = 56$ .

6 0

3 years ago

Ann is mailing packages. Each small package costs her $2.10 to send. Each large package costs her $3.30. How much will it cost h

Liula [17]

Answer:

$35.76

Step-by-step explanation:

12.60

23.10

--------

35.76

4 0

2 years ago

Read 2 more answers

PLEASE HELP FAST!!!

larisa [96]

I believe the answer is 4

6 0

2 years ago

Read 2 more answers

We will now use energy considerations to find the speed of a falling object at impact. Artiom is on the roof replacing some shin

ohaa [14]

Answer:

v = 8.49 m/s rounded off to 3 significant figures

Step-by-step explanation

Using Energy Conservation

U = Tk + Vp (Sum of kinetic Tk Energy and gravitational potential Vp Energy)

At height = 3.67 m, the hammer was still or the velocity was negligible; hence, vi = 0 m/s.
Ui = 0 + mgh
At ground all potential energy is converted to kinetic; hence, Uf = $\frac{1}{2}$ mv².
Since total energy of the system remains constant we equate Ui to Uf.
Ui = Uf
mgh = $\frac{1}{2}$ mv²
After cancelling out masses and making v the subject of the formula we get:

v = $\sqrt[2]{2gh}$ = $\sqrt[2]{2*9.81*3.67}$ = 8.49 m/s rounded off to 3 significant figures

3 0

3 years ago