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eduard
4 years ago
15

Area

Mathematics
1 answer:
pentagon [3]4 years ago
8 0

Step-by-step explanation:

1. In PQN & SRT.

a. <RST=<QPN (corresponding angle PQllSR)

b. <STR = <PNQ (corresponding angle TRIINQ)

c. TR=QN (Since TN & QN are opp. Side of parallelogram QNTR)

d. .°.PQN~=SRT.

2.PQN=PSOQ+SNO (whole part axiom)

3.SRT = SNO + NTRO(same as above)

4. PQN=SRT (From st. 1d)

or, PS0Q+SNO =SNO + NTRO (Cancellation of SNO)

or, PS0Q=NTRO

or, PSOQ +QOR=NTRO +QOR (Adding QOR on both side)

or, .°.◼️PQRS = ◼️QRTN

Best of luck!!!!.

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Read 2 more answers
Which of the following linear relationships is NOT also a proportional relationship?
katen-ka-za [31]

The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x  , y = - (1/2)x  .

A linear relationship in the form of y = mx + c is said to be a proportional relationship when c = 0  .

in the question

Part(a)

the equation is  y = (2)x - 3

on comparing it with y = mx + c , we get c = -3 , which is not 0 .

So , it is not a proportional relationship .

Part(b)

the equation is  y = (-2)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Part(c)

the equation is  y = (3/5)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Part(d)

the equation is  y = - (1/2)x

on comparing it with y = mx + c , we get c = 0 ,

So , it is a proportional relationship .

Therefore, The linear relationships that are proportional relationship are y = (-2)x , y = (3/5)x  , y = - (1/2)x  , that are options (b) , (c) and (d) .

The given question is incomplete , the complete question is

Which of the following linear relationships is NOT also a proportional relationship?

(a) y = (2)x - 3

(b) y = (-2)x

(c) y = (3/5)x

(d) y = - (1/2)x

Learn more about Proportionality here

brainly.com/question/14967814

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