From a survey of 60 students attending a university, it was found that 9 were living off campus, 36 were undergraduates, and 3 w
ere undergraduates living off campus. find the number of these students who were
1 answer:
I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus
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Answer:
Option D
Step-by-step explanation:
We are given the following equations -
It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -
First, I swapped the first and third rows.
Leading coefficient of row 2 canceled.
The start value of row 3 was canceled.
Matrix rows 2 and 3 were swapped.
Leading coefficient in row 3 was canceled.
And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -
The positioning of the zeros indicated that there was no solution!
<u><em>Hope that helps!</em></u>