Using the law of logarithm. LogA - LogB = Log(A/B)
log(x²-y²) - log(x-y) = log((x²-y²)/(x-y))
Note by difference of two squares, (x²-y²) = (x-y)(x+y)
Simplifying (x²-y²)/(x-y) = (x-y)(x+y)/(x-y) = (x+y)
Therefore log(x²-y²) - log(x-y) = log((x²-y²)/(x-y)) = log((x-y)(x+y)/(x-y)) = log(x+y)
Question 1: 4.375/10 of an hour (or 26.25 minutes)
Answer:
18y^3 + 24y^5.
Step-by-step explanation:
6y^3(3 + 4y^2)
= 6*3 y^3 + 6*4 y^(3+2)
= 18y^3 + 24y^5.
16+ 44 so I =60 hdndmoaoaoajebdbvdjjssksk
