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Drupady [299]
4 years ago
13

I need help on this....

Mathematics
1 answer:
pychu [463]4 years ago
3 0
I'm not exactly sure what the T-Chart method is, but you can find the original amount of money Ronald had by adding $123.45 and $36.55 together. Hope this helps!
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Janice works for a salary of $2,396 per month. She has federal income tax withheld at the rate of 15 percent, Social Security ta
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Her pay will be ....

... $2396 × (100% -15% -6.2% -1.45%) -$95

... = $2396 × 0.7735 - 95

... = $1758.31

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How much is $800 bonus for a year add to your hourly rate​
masha68 [24]

Answer:

eine Menge Geld

Step-by-step explanation:

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Wittaler [7]
The coefficient is a number that is placed in front of the variable for which It is being multiplied to. In this case it would be 5.

Constants are values that can be thought of as the opposite of coefficients in that they do not have any other variables or letters and thus they include only a number.

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3 years ago
I’m stuck can some one help me
abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-7, x_2=-10,y_2=8

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

We have x_1=2, y_1=-10, x_2=3,y_2=10

Putting values and finding midpoint

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

x^2-3x-28

We will break the middle term and find factors

x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

x^2+6x+8

We will break the middle term and find factors

x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)

So, the factors are (x+4)(x+2)

Option A is correct.

7 0
3 years ago
What does 5+2x(x-8) equal?
Tems11 [23]
2x to 2nd power - 16x + 5
5 0
3 years ago
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