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3 years ago

Simplify the expression 3(2+q)+15 simplified is

Mathematics

2 answers:

HACTEHA [7]3 years ago

6 0

6+3q+15

3q+21 this is the correct answer

MrRa [10]3 years ago

4 0

ANSWER: 51 + 3q

STEP BY STEP:

Rewrite the equation ⇩

3(2+q) + 15

Distribute ⇩

6 + 3q + 45

Combine like terms (6+45) ⇩

51 + 3q

Enjoy your final answer. Hope that helped ★

51 + 3q

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Please give a simple summary of log functions.

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4 years ago

Ted has some red blocks and some green blocks.

MakcuM [25]

A red block is 2 ounces and a green block is 4. This would make the answer 6 for the total weight of one of each block.

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3 years ago

Doug earns $10.50 per hour working at a restaurant. On

alexira [117]

First, add all of the working hours.
1 $\frac{3}{4}$ + 2 $\frac{1}{3}$ + 1 $\frac{5}{12}$

Since the denominators are different, make them all the same.
1 $\frac{9}{12}$ + 2 $\frac{4}{12}$ + 1 $\frac{5}{12}$

Add everything together.
4 $\frac{1}{12}$ + 1 $\frac{5}{12}$ = 5 $\frac{6}{12}$

Then, simplify.
5 $\frac{1}{2}$ or 5.5

Multiply the time by the salary.
<span>5.5*10.5= Doug earned $57.75</span>

3 0

3 years ago

A simple random sample of size nequals=8181 is obtained from a population with mu equals 77μ=77 and sigma equals 27σ=27. (a) De

ivanzaharov [21]

Answer:

a) $P(\bar X>81.5)=1-0.933=0.067$

b) $P(\bar X$

c) $P(73.4$

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

$X \sim N(\mu=77,\sigma=27)$

And let $\bar X$ represent the sample mean, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

On this case $\bar X \sim N(77,\frac{27}{\sqrt{81}})$

Part a

We want this probability:

$P(\bar X>81.5)=1-P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >81.5)=1-P(Z$

$P(\bar X>81.5)=1-0.933=0.067$

Part b

We want this probability:

$P(\bar X\leq 69.5)$

If we apply the formula for the z score to our probability we got this:

$P(\bar X \leq 69.5)=P(Z\leq \frac{69.5-77}{\frac{27}{\sqrt{81}}})=P(Z$

$P(\bar X\leq 69.5)=0.0062$

Part c

We are interested on this probability

$P(73.4$

If we apply the Z score formula to our probability we got this:

$P(73.4$

$=P(\frac{73.4-77}{\frac{27}{\sqrt{81}}}$

And we can find this probability on this way:

$P(-1.2$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1.2$

3 0

4 years ago

The cost of a circular table is directly proportional to the square of the radius. A circular table with a radius of 50cm costs

Lana71 [14]

Answer:

£135 is the correct answer.

Step-by-step explanation:

Let C be the cost of table.

And let R be the radius of table.

Cost of table is directly proportional to square of radius.

As per question statement:

$C\propto R^{2}$ or

$C=a\times R^2 ....... (1)$

where $a$ is the constant to remove the $\propto sign$ .

It is given that

$C_1 =$ £60 and $R_1 = 50\ cm$

$C_2 = ?$ when $R_2= 75\ cm$

Putting the values of $C_1$ and $R_1$ in equation (1):

$60=a \times 50^2 ....... (2)$

Putting the values of $C_2$ and $R_2$ in equation (1):

$C_2=a \times 75^2 ....... (3)$

Dividing equation (2) by (3):

$\dfrac{60}{C_2}= \dfrac{a \times 50^2}{a \times 75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{50^2}{75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{2^2}{3^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{4}{9}\\\Rightarrow C_2 = 15 \times 9 \\\Rightarrow C_2 = 135$

So, <em>£135 is the correct answer</em>.

7 0

3 years ago