Ask question

Ask question

All categories

11111nata11111 [884]

3 years ago

5

Can someone please help me with number 22?

1 answer:

yuradex [85]3 years ago

3 0

Ronaldo's age = 13
after 5 years, his age = 13+5 = 18 years

After 5 years, Marissa's age = 18 * 2/3 = 12 years
Present age of marissa = 12 - 5 = 7 years
in 3 years, marissa's age = 7 + 3 = 10 years

Marissa will be 10 years old in 3 years.

Hope it helps!

You might be interested in

What is the measure of angle A?

antoniya [11.8K]

Answer:

A = 19.47

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hypotenuse

sin A = 2/6

Take the inverse sin of each side

sin ^-1 ( sin A) = sin ^-1 (2/6)

A =19.47122063

To the nearest hundredth

A = 19.47

3 0

4 years ago

For which angles 0, is sin (0) negative? Select all that apply

musickatia [10]

Answer:

In the 3rd and 4th quadrants of the coordinate system

ie π < θ < 2π. At π and 2π the sine values are zero

Step-by-step explanation:

6 0

2 years ago

What's 1.27 repeating as a fraction

svet-max [94.6K]

As a improper fraction, its 127/100

5 0

3 years ago

Which values of P and Q does the following equation have infinitely many solutions?

vladimir1956 [14]

Any value as long as P = Q

For the equation to have infinitely many solutions, we require both sides of the equation to have exactly the same terms.

4 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago