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Likurg_2 [28]
1 year ago
10

Translate the sentence into an equation.

Mathematics
1 answer:
xxTIMURxx [149]1 year ago
8 0

Answer:

8b + 9 = 7

Step-by-step explanation:

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2. Find the compound interest on Rs.25, 000 after 2 years compounded
Allushta [10]

Answer:25,000 in 2 years at annual compound interest, if the rates for the successive years be 4% and 5% per annum respectively is: (1) Rs. 30,000 (2) Rs. 26,800 fa) Rs.

A=P[1+  

100

r

​  

]  

n

 

⇒  A=Rs.25,000×(  

100

106

​  

)  

3

 

⇒  25,000×  

50

53

​  

×  

50

53

​  

×  

50

53

​  

 

⇒  A=Rs.29,775.40

⇒  CI=A−P

⇒  Rs.29,775.40−Rs.25,000

∴   CompoundInterest=Rs.4775.40.

6 0
3 years ago
2032 is decreased by 8%. What is the value after the decrease?
Serga [27]

Answer:

1869.44

Step-by-step explanation:

The 8% of 2032 is 162.56

2032-162.56=1869.44

brainliest if right pls

4 0
2 years ago
Help please! Lily records the change in her dogs weight over 4 weeks what is the dogs average weekly weight change
madreJ [45]

Answer:

mabe divided by 2

Step-by-step explanation:

3 0
3 years ago
Bbnvbncvbnvbnvbnvbnx
max2010maxim [7]
Very nice question. glad to see you’re exploring your education with gibberish’
7 0
2 years ago
The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.
Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

<em>Let X = number of hours spent per week on household chores</em>

So, assuming data follows normal distribution; X ~ N(\mu=28,\sigma^{2}=7^{2})

The z score probability distribution for sample mean is given by;

               Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = mean hours = 28

            \sigma = standard deviation = 7 hours

            n = sample of adults = 49

<em>Let </em>\bar X<em> = sample mean hours spent per week on household chores</em>

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P(\bar X > 26.75 hours)

    P(\bar X > 26.75 hours) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{26.75-28}{\frac{7}{\sqrt{49} } } ) = P(Z > -1.25) = P(Z < 1.25)

                                                                     = 0.89435  {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

4 0
2 years ago
Read 2 more answers
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