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4 years ago

Determine which postulate or theorem can be used to prove that LMO ~ NMO.

Mathematics

2 answers:

Lemur [1.5K]4 years ago

8 0

Answer:

AAS

Step-by-step explanation:

AlladinOne [14]4 years ago

4 0

Given in the picture are two triangles with common side OM.

L and N are on either side of OM

In triangles OML and OMN, given that

angle L = angle N

and OM is perpendicular to LN.

Hence in these two triangles OML, and OMN we have

OM=OM (reflexive property)

Angle L = angle N(given)

Angle OML = angle OMN (perpendicular)

Thus two angles and one corresponding side are equal

Hence by AAS property the two triangles are congruent.

(since side is not included by the angles)

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babunello [35]

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We apply distributive property to the terms within parentheses:

$-12s + 6 = 30$

Subtracting 6 from both sides of the equation we have:

$-12s = 24$

Dividing between -12 on both sides of the equation:

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B) $-3m = -5 (m-8)$

We apply distributive property to the terms within parentheses:

$-3m = -5m + 40$

We add 5m on both sides of the equation:

$2m = 40$

Dividing between 2 on both sides of the equation:

$m = \frac {40} {2}\\m = 20$

C) $7 (2-g) = 49$

We apply distributive property to the terms within parentheses:

$14-7g = 49$

We subtract 14 from both sides of the equation:

$-7g = 35$

Dividing between -7 on both sides of the equation:

$g = \frac {35} {- 7}\\g = -5$

D) - $7 (3w + 4) = 14$

We apply distributive property to the terms within parentheses:

$-21w-28 = 14$

We add 28 to both sides of the equation:

$-21w = 42$

Dividing between -21 on both sides of the equation:

$w = \frac {42} {- 21}\\w = -2$

Answer:

$s = -2\\m = 20\\g = -5\\w = -2$

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