y=f(x³y-3),(y-2)
Step-by-step explanation:
(x,y)>(x-2+y3)
(x,y)(x+3,y-3) or (x+y)
hope it's help
<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>
Use a calculator!
Or if you must,
2.4 rounded down is 2.
12 divided by 2 is 6 so the answer would be less than but not greater than 6.
We know that
if sin A=cos B
then
angle A and angle B are complementary angles
so
A+B=90°
in this problem
(x+21)+<span>(2x+21)=90-------> 3x+42=90-------> 3x=48-----> x=16</span>°
