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Serggg [28]
3 years ago
6

Mark and ann together were allocated n boxes of cookies to sell for a club project. mark sold 10 boxes less than n and ann sold

2 boxes less than n. if mark and ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n ?
Mathematics
2 answers:
LekaFEV [45]3 years ago
7 0

Answer:

n=11

Step-by-step explanation:

Let m represent the number of boxes sold by mark and a represent the number of boxes sold by Ann.

We have been given that Mark sold 10 boxes less than n. We can represent this information in an equation as:

m=n-10...(1)

We are also told that Ann sold 2 boxes less than n. We can represent this information in an equation as:

a=n-2...(1)

Further, we are told that together they have sold less than n boxes. We can represent this information in an inequality as:

a+m  

Now we will use substitution method to solve our system of equations.

Upon substituting equation (1) and (2) in (3) we will get,

n-2+n-10  

2n-12  

2n  

2n-12+12  

2n-n  

n  

The integer less than 12 is 11, therefore, the value of n is 11.

Lady bird [3.3K]3 years ago
3 0
<span>n = 11<span>.

Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.

Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.

Together, they sold n-10+n-2=2n-12 boxes.

We know that they sold less than n boxes, so our inequality would be
2n-12<n.

To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.

Add 12 to both sides:
n-12+12<0+12; n<12.

This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.

If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box.  </span></span>
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Step-by-step explanation:

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Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

Step-by-step explanation:

Here are the options:

A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.

B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

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At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:

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Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

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