PLZ HALP!! I need this to be done ASAP!!

Which decimals as the same value as 2 divided by 5

LenKa [72]

Answer:

anything that ends in 0 like .10

5 0

2 years ago

Read 2 more answers

How do I begin this equation

alex41 [277]

Trigonometry:
We know that csc x = 1 / sin x and π = 180°;
sin 5π/ 6 = sin 150° = 1/2
csc 2π / 3 = 1 / sin 120° = 1 / √3/2 = 2 / √3
Finally:
4 · 1/2 + 7 · ( 2 / √3 )² = 2 + 7 · 4/3 =
= 2 + 28/3 = 2 + 9 1/3 = 11 1/3

5 0

3 years ago

Please Answer, No links! reporting right away!.. giving brainliest and more points!

loris [4]

Answer:

A) 154x89 _s2

s

Step-by-step explanation:

A) 154x89 _s2

sA) 154x89 _s2

s

4 0

2 years ago

Help me please!!! I'll give brainlist and thanks! Just please help me!!

Alex_Xolod [135]

Answer:How many fives are in 15? ... How many three-fourths are in 2? ... There are 6 half-sized pieces in 3 wholes. ... and we can see that there are 4 wholes with 6 sixths in each whole, so there are 4\times 6 = 24 sixths in 4. ... Each whole yields a two-thirds and one half of another two-thirds, therefore 3 sets of two-thirds can be ...

Step-by-step explanation:

8 0

3 years ago

A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours a

natita [175]

Answer:

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, . . . , x₂₃ be the actual data observed by the student

The sample means = x₁ + x₂ + . . . , x₂₃ / 23

$= \frac{x_1 +x_2 +...x_2_3}{23}$

= 2.3hr

⇒ $\sum xi =2.3 \times 23 = 52.9hrs$

let x₁ , x₂, . . . , x₂₃ arranged in ascending order

Then x₂₃ was 10 and has been changed to 14

i.e x₂₃ increase to 4

Sample mean $= \frac{x_1 +x_2 +...x_2_3}{23}$

$\frac{52.9hrs + 4}{23} \\\\= \frac{56.9}{23} \\\\= 2.47$

therefore, the new sample mean is 2.47

2) For the old data set

the median is $x_1_2(th)$ values

$[\frac{n +1}{2} ]^t^h value$

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = $[{x_1_2]^t^h value$ remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

$=\sqrt{\frac{1}{n-1} \sum (xi - \bar x_{old})^2 } \\\\=\sqrt{\frac{1}{22}\sum ( xi - 2.3)^2 }---(1)$

The new sample standard sample deviation is calculated as

$= \sqrt{\frac{1}{n-1} \sum (xi-2.47)^2} ---(2)$

Now, when we compare (1) and (2) the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)² ∑ (xi - 2.47)²

Therefore , the standard deviation increases

6 0

3 years ago