I don't know what is the question
but this is the pictures of the points
good luck
Use the Pythagorean Theorem:
a^2 + b^2= c^2
a= one side= 68 mi
b= second side= 80 mi
c= hypotenuse= Greenville to Columbia mi
a^2 + b^2= c^2
68^2 + 80^2= c^2
square each number
4,624 + 6,400= c^2
11,024= c^2
take square root of both sides
104.995 mi= c
ANSWER: The distance from Greenville to Columbia is 104.995 miles (rounded to 105 miles).
Hope this helps! :)
Answer: w ≤ 14 cm , L ≤ 42 cm
<u>Step-by-step explanation:</u>
width (w): w
Length(L): 3w
Perimeter (P) = 2w + 2L
P ≤ 112
2w + 2L ≤ 112
2(w) + 2(3w) ≤ 112
2w + 6w ≤ 112
8w ≤ 112
w ≤ 14
Answer : a
step by step explanation :
