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denis23 [38]
3 years ago
6

Find the range of y = 3cos4x - 2. -5 ≤ y ≤ 5 -5 ≤ y ≤ 1 -3 ≤ y ≤ 3 1 ≤ y ≤ 3

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

the CORRECT answer option number 2

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Step-by-step explanation:

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yanalaym [24]

Answer:

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given \: equations \: are \\ 3x + 4y = 0 \:  \: and \: 2x + 3y = 1  \\ multiply \: by \: 2 \: in \: first \: equation \\ 6x + 8y = 0 \\ multiply \: by \: 3 \: in \: second \: equation \\ 6x + 9y = 3 \\ subtracting \: the \: above \: mentioned \: equation \:  \\  we \: get \:  - y =  - 3 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  y = 3 \\ substitute \: y = 3 \: in \: first \: equation \\ 3x + 4(3) = 0 \\ 3x =  - 12 \\ x =  - 4

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
2 years ago
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