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Sedaia [141]
3 years ago
5

What is the slope of a line that passes through the points (-5,-3) and (9,-6)

Mathematics
1 answer:
kipiarov [429]3 years ago
7 0
To find the slope given two points, you need to subtract the two y values over the two x values
(-5,-3)  (9,-6)
-5 will be x1, and -3 will be y1. 9 will be x2, and -6 will be y2. You then need to put the numbers in the correct place in the equation.
y2-y1      -6-(-3)     -9
-------- =   -------- =  ----
x2-x1       9-(-5)     14
Now that we have the slope (-9/14) you can use one of the coordinates to find the value of b.
Let's use (9,-6).
-6=-9/14(9)+b
-6=-81/14+b
+81/14
b=-3/14
Your final equation is y=-9/15x-3/14


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1.) Which system of equations below give the solution (-1,-2)?
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Answer:

y = -x - 3

Step-by-step explanation:

Plug in -1 for <em>x</em><em> </em>and your result will come out to 1 because of that double negative [-(-1) = 1]. Next, deduct 3 from 1 to get -2.

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3 years ago
A cone has radius 5x cm and a height 12x cm.A sphere has radius r cm.The cone has the same total surface area as the sphere.Show
Lana71 [14]

Answer:

r^2 = 45÷2 x^2

Step-by-step explanation:

Details of cone:

Radius(r) = 5x cm

Height(h) = 12x cm

Slant height(l) = √(12x^2 + 5x^2)

l = 13x cm

Total surface area of a cone (T. S. A) = πrl + πr²

T. S. A = π * 5x * 13x + π5x^2

T.S.A = π65x^2 + π5x^2

T.S.A = π65x^2 + π25x^2

T.S.A = 90πx^2 - - - - - (1)

Details of sphere:

Radius (r) = r cm

Total surface area = 4πr²

Total Surface area of sphere= 4πr²cm - - - (2)

Equating (1) and (2) to calculate r

4πr² = 90πx^2

r^2 = 90πx^2 / 4π

r^2 = 90π (x^2) / 4π

r^2 = 45/2 (x^2) ;

r^2 = 45÷2 x^2

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8 0
3 years ago
On average,ea rectangular garden ha an area of 144 meter square. During a redesign of the garden center, the dimension of the re
aksik [14]

Answer:

New dimensions are; Width = 12m and Length = 12m

Step-by-step explanation:

Let length of rectangle be L

Let width be W

Area of rectangle has a formula;

Area = Length x Width = LW

We are given the area = 144 m²

So,

LW = 144 - - - (eq1)

Now, we are told that width is doubled and length is decreased by 12m but area remains the same.

Thus, we have;

Width as 2W and Length as L - 12.

Area = 2W(L - 12)

So,

2W(L - 12) = 144 - - - (eq2)

Equating eq 1 and 2,we have;

LW = 2W(L - 12)

W will cancel out to give;

L = 2(L - 12)

L = 2L - 24

2L - L = 24

L = 24m

From equation 1, LW = 144

Thus; W = 144/L = 144/24

W = 6m

So new design of rectangle now has a dimension of;

Width = 2W = 2 × 6 = 12m

Length = L - 12 = 24 - 12 = 12m

So, new dimensions are; Width = 12m and Length = 12m

5 0
3 years ago
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