What is the slope of a line that passes through the points (-5,-3) and (9,-6)

1 answer:

7 0

To find the slope given two points, you need to subtract the two y values over the two x values
(-5,-3) (9,-6)
-5 will be x1, and -3 will be y1. 9 will be x2, and -6 will be y2. You then need to put the numbers in the correct place in the equation.
y2-y1 -6-(-3) -9
-------- = -------- = ----
x2-x1 9-(-5) 14
Now that we have the slope (-9/14) you can use one of the coordinates to find the value of b.
Let's use (9,-6).
-6=-9/14(9)+b
-6=-81/14+b
+81/14
b=-3/14
Your final equation is y=-9/15x-3/14

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Slope is –2 & (5, 3) is on the line.<br> Y-Intercept:<br> Equation of the line (no spaces):

GREYUIT [131]

Answer:

The y intercept is (0,13)

The equation of the line is y = -2x+13

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -2x+b

Substituting the point

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3 = -10 +b

Add 10 to each side

13 =b

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Answer:

Final answer is c=-7.

Step-by-step explanation:

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We know that standard form of quadratic equation is given by $ax^2+bx+c=0$ .