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3 years ago

The equations of four lines are given. Identify which lines are perpendicular.

Mathematics

1 answer:

Kipish [7]3 years ago

4 0

Put it in Desmos and look at the graph virtually so you can have a better idea

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Y=-1/4x+6 when y equals 4

timofeeve [1]

Answer:

Step-by-step explanation:

Y = -1/4x+6, when y= 4

Same as saying

4 = -1/4x+6 , where y = 4

Multiply both sides by (4x+6)

4(4x+6) = -1

Opening the parentheses

16x + 24 = -4

16x = -4-24

16x = -28

Divide both sides by 16

X = -28/16

X = - 7/4

Ans = -7/4

8 0

3 years ago

I need help ( kinda urgent )

Alenkinab [10]

Answer:

The answer is B.

mark me brainliest!

8 0

3 years ago

Read 2 more answers

In the right ΔABC, AN is the altitude to the hypotenuse. Find BN, AN, and AC, if AB=2√5 in and NC= 1 in.

kipiarov [429]

Answer:

$BN=4\ \text{in}$

$AN=2\ \text{in}$

$AC=\sqrt{5}\ \text{in}$

Step-by-step explanation:

Let $BN=x$

$BC=c$

$NC=y=1\ \text{in}$

$AB=a=2\sqrt{5}\ \text{in}$

$AC=b$

We have the relation

$\dfrac{BC}{AB}=\dfrac{AB}{BN}\\\Rightarrow \dfrac{c}{a}=\dfrac{a}{x}\\\Rightarrow c=\dfrac{a^2}{x}\\\Rightarrow x+1=\dfrac{a^2}{x}\\\Rightarrow x^2+x=20\\\Rightarrow x^2+x-20=0\\\Rightarrow x=\frac{-1\pm \sqrt{1^2-4\times 1\times \left(-20\right)}}{2\times 1}\\\Rightarrow x=4,-5$

$\boldsymbol{BN=4\ \text{in}}$

$h=\sqrt{a^2-x^2}\\\Rightarrow h=\sqrt{(2\sqrt{5})^2-4^2}\\\Rightarrow h=2\ \text{in}$

$\boldsymbol{AN=2\ \text{in}}$

$b=\sqrt{h^2+y^2}\\\Rightarrow b=\sqrt{2^2+1^2}\\\Rightarrow b=\sqrt{5}\ \text{in}$

$\boldsymbol{AC=\sqrt{5}\ \text{in}}$

8 0

3 years ago

Leonardo makes the following purchases at the store: 1 backpack for $16.89 5 spiral notebooks for $1.19 each 1 pack of mechanica

solong [7]

I believe the correct answer is he paid the right amount

3 0

4 years ago

Read 2 more answers

Solve for x x + y = 1 x + 7y = -4 2x - 6y = 4 5x + 15y = -10 2x + 6y = 10

Arada [10]

X + y = 1
add - y both sides
x + y + - y = 1 + - y
x = - y + 1
Answer: x = - y + 1
Graph: y = - x + 1

x + 7y = - 4
add - 7 both sides
x + 7y + - 7y = - 4 + -7y
x = - 7y - 4
Answer: x = - 7y - 4
Graph: y = 0.142857x - 0.571429

2x - 6y = 4
add 6y to both sides
2x - 6y + 6y = 4 + 6y
2x = 6y + 4
divide both sides by 2
2x/2 = 6y + 4/2
x = 3y + 2
Answer: x = 3y + 2
Graph: y = 0.333333x - 0.666667

5x + 15y = - 10
add - 15 to both sides
5x + 15y + - 15y = - 10 + - 15y
5x = - 15y - 10
divide both sides by 5
5x/5 = - 15y - 10/5
x = - 3y - 2
Answer: x = - 3y - 2
Graph: y = - 0.333333x - 0.666667

2x + 6y = 10
add - 6y to both sides
2x + 6y + - 6y = 10 + - 6y
2x = - 6y + 10
divide both sides by 2
2x/2 = - 6y + 10/2
x = - 3y + 5
Answer: x = -3y + 5
Graph: y = - 0.333333x + 1.666667

Hope that helps!!!

8 0

3 years ago