Please help answer this correctly!!! will mark brainliest!!!

Mathematics

1 answer:

AVprozaik [17]3 years ago

6 0

2) B
3)C

I’m not sure If im right but this is what I think it is :)

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The perimeter of triangle ABC is 54. the triangle has side lengths AB=3x, BC=4x, AC=5x. Find the length of each side.

elena-14-01-66 [18.8K]

The perimeter of a triangle is the sum of its sides. So, we have

$P = \overline{AB}+\overline{BC}+\overline{AC}$

We have an exact value for the perimeter, and variable expressions for the sides. Let's substitute the formula above with what we're given:

$54 = 3x+4x+5x = 12x$

If you divide both sides by 12, you have

$x = \dfrac{54}{12} = 4.5$

So, the lengths of the sides are

$AB = 3x = 3\times 4.5 = 13.5$

$BC = 4x = 4\times 4.5 = 18$

$AC = 5x = 5\times 4.5 = 22.5$

7 0

3 years ago

A game is played with a played pentagonal spinner with sides marked 1 to 5. The scorer is on the side which comes to rest on the

slava [35]

Answer: probability of getting two 5s =0.04

probability of getting at least one 5 =0.36

probability of getting a total score greater than 5 =0.6

Step-by-step explanation:

Total outcomes on 1 spinner = 5

Then , total outcomes of spinning it 2 times= $5\times5 = 25$

Number of outcomes for getting two 5's = 1

Then, the probability of getting two 5s $=\dfrac{\text{Favorable outcomes of getting two 5's }}{\text{Total outcomes}}$

$=\dfrac{1}{25}=0.04$

Number of outcomes for getting at least one 5 [ {(1,5),(2,5),(3,5),(4,5),(5,5), (5,1), (5,2), (5,3), (5,4)} ] =9

Then, the probability of getting at least one 5 $=\dfrac{\text{Favorable outcomes of getting at least one 5 }}{\text{Total outcomes}}$

$=\dfrac{9}{25}=0.36$

Number of outcomes for getting a total score of 5, [ {(1,4),(4,1),(2,3),(3,2)} ] =4

Then, the probability of getting a total score of 5, $=\dfrac{\text{Favorable outcomes of getting a total score of 5 }}{\text{Total outcomes}}$

$=\dfrac{4}{25}$

Number of outcomes for getting a total score greater than 5 [ {(1,5),(5,1),(2,4),(4,2),(2,5), (5,2), (3,4),(4,3), (3,5), (5,3), (3,3), (4,5), (5,4), (4,4), (5,5)} ] =15

Then, the probability of getting a total score greater than 5, $=\dfrac{\text{Favorable outcomes of getting a total score greater than 5 }}{\text{Total outcomes}}$