All categories

3 years ago

Sending text messages from Katrina's cell phone costs $0.19 per text message. From last month, she has a credit on her bill for

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

Answer:

Katrina will have to pay $21.02 this month.

Step-by-step explanation:

The cost per text message = $0.19

Last month credit = $9.50

The number of text messages sent this month = 158

So, the total cost of 158 texts = 158 x cost per text

= 158 x $0.19 = $ 30.52

So, her total bill = The amount spent on texts - The credit amount

= $ 30.52 - $9.50 = $21.02

So, Katrina will have to pay $21.02 this month.

You might be interested in

universal pet house sells vinyl doghouses and treated lumber doghouses. It takes the company 5 hours to build a vinyl doghouse a

I am Lyosha [343]

5x + 2y = 50

x + 2y = 30

6 0

3 years ago

Read 2 more answers

Please help x 15 points

katovenus [111]

A(0,-1)
B(3√3/3, 2)

Slope of AB = (y₂ - y₁)/(x₂-x₁)
Slope = (2-1)/(√3/3 , -0)

Slope = 1/√3/3 = 1/√3 = √3/3

OR SLOPE = tan(a°) = √3/3 and a° = 30°

3 0

3 years ago

Which of the following could be the number of real roots, including any repeated roots, of a quadratic polynomial with real coef

scoray [572]

I think the only answer here is 0
Idk tho

5 0

3 years ago

The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu

m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. $\mu=23.50$

$\sigma=5$

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let $\overline{x}$ be the sample mean.

Formula : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Then, the probability that the sample mean is at least $25.00 will be :-

$P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z$

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0

3 years ago

I need help please and thank you

omeli [17]

Oof I’m not quite sure how to do that

8 0

3 years ago