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Masteriza [31]
3 years ago
6

The data to represent average test scores for a class of 24 students includes an outlier value of 89. If the mean, including the

outlier of 89, equals 77, which statement is always true about the new data when the outlier is removed?
The mean would increase.
The mean would decrease.
The median would increase.
The median would decrease.
Mathematics
1 answer:
faltersainse [42]3 years ago
8 0

Answer:

The mean would decrease.

Step-by-step explanation:

If the mean score of 24 students is 77.

The total score of 24 students = 24 x 77 = 1848

If the outlier is removed, the mean would become

New total score / number of students = (1848 - 89) / (24 - 1)

1759/23 = 76.5

It can be seen that the mean decreased.

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There are a total of 15 dimes and quarters in a covered cup. The value of all 15 coins totals 2.85
QveST [7]

Answer:

There are 6 dimes and 9 quarters.

Step-by-step explanation:

Represent the number of dimes and the number of quarters by d and q.

Then d + q = 15, or q = 15 - d.

Also, ($0.25)q + ($0.10)d = $2.85, or 5q + 2d = 57.

Substituding 15 - d for q, we get 5(15 - d) + 2d = 57, or

75 - 5d + 2d = 57, or

75 - 3d = 57, or

3d = 18.  Thus, there are 6 dimes.  Since q = 15 - d, q = 15 - 6 = 9.

There are 6 dimes and 9 quarters.

6 0
4 years ago
8.4×0.5 showing work​
Katen [24]
Can u add a picture?
8 0
3 years ago
Find an equation for the nth term of the arithmetic sequence. a18 = 97, a20 = 281
Ipatiy [6.2K]
Hope this helped the answer is in purple

5 0
4 years ago
2x - 8<br> X-3<br> 4. What is the value of x?<br> (a) 3<br> (c) 9<br> (b) 15<br> (d) 30<br> 5<br> 3
azamat
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5 0
3 years ago
The diameter of a sphere is 2,160 mm. The diameter of a second sphere is 7,520 mm. Approximately how many times larger is the vo
fgiga [73]

Answer:

Approximately 42 times larger

Step-by-step explanation:

The diameter of a sphere is 2,160 mm.

The diameter of a second sphere is 7,520 mm.

To see how many times larger is the diameter of second sphere is than the diameter of the second sphere, we divide to get:

k =  \frac{7520}{2160}

k = 3.481

To see how many times larger the volume is, we cube both sides

{k}^{3}  =  {3.481}^{3}

This implies that

{k}^{3}  = 42.181

Therefore the volume of the second sphere is approximately 42 times larger

3 0
4 years ago
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