PB and J Array
1 answer:
let
x----------> number of square jam sandwiches of Ken in the side x of rectangle
y---------> number of square jam sandwiches of Ken in the side y of rectangle
A1-------------> total number of square jam sandwiches of Ken
A2-------------> total number of square jam sandwiches of Sara
we know that
A1=xy
A2=[(x+2)(y+2)-xy]
A1=A2
xy=[(x+2)(y+2)]-xy------------ > xy=xy+2x+2y+4-xy
xy-2y=2x+4-------- > y=[2x+4]/[x-2]
testing different values of x to get a pair of whole numbers--> see the table attached I find 2 solutions<span>1) x=3 and y=10
</span>A1=3*10=30
A2=30<span>
total number of sandwiches of Ken------ > 30
</span>total number of sandwiches of Sara------ > 30
<span>
2) <span>x=4 and y=6
</span></span>A1=4*6=24
A2=24<span>
total number of sandwiches of Ken------ > 24
</span><span>total number of sandwiches of Sara------ >24</span>
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Answer:
a)
b) ≈ 0.76
Step-by-step explanation:
Given that : Y1 < Y2 < Y3 < Y4 < Y5 are the order statistics of five independent observations
mean of θ = 3
<u>a) Determine the P.d.f of the sample median </u>
P.d.f of sample median ( y3 ) =
attached below is the detailed solution
<u>b) determine the probability that Y4 is < 5 </u>
p( Y4 < 5 ) = G4( 5 )
= 0.7599 ≈ 0.76
attached below is the detailed solutions
A cheap way to go about it is, use the LCD and multiply both sides by it.
now, notice the denominators, x, 4, 4x, clearly the LCD is 4x, so let's multiply both sides by that, to do away with the denominators,
now, notice the denominators, x, 4, 4x, clearly the LCD is 4x, so let's multiply both sides by that, to do away with the denominators,