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3 years ago

HELP I NEED HELP ASAPD DHEWUHFWUFHWKEJFB;KWFBEUFB;KWEGFWKFJBWKBFKWEFBIWEUFBWIEFBWEIBFWEFBIWUEFIWEU HEP !!! ANSWER PLEASE!!

Mathematics

1 answer:

katen-ka-za [31]3 years ago

8 0

Answer:

I think it's 25

Step-by-step explanation:

I used a protractor

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3 years ago

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Find the volume of a cone with a height of 12 and a base diameter of 6.

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Answer: 466.56

Step-by-step explanation:

Volume = pi times radius^2 times height/3

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Volume = 3.24 times 6^2 times 12/3

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2 years ago

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2 years ago

What should be added to p to get p+q?

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Step-by-step explanation:

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3 years ago

What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

<u>Part a: The height of the ball when t = 2 seconds:</u>

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

<u>Part b: The height of the ball when t = 4 seconds:</u>

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$

Simplifying the terms, we get;

$h(4)=-256+320+4$

$h(4)=68$

Thus, the height of the ball after 4 seconds is 68 feet.

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3 years ago