Y = mx + c
-4 = 2(3) + c
-4 = 6 + c
-10 = c
y = mx + c
y = 2x - 10
Hence, the equation is y=2x-10.
Answer:
JKLM is a parallelogram
Explanation:
The slope m of a line through two points (x1,y1) and (x2,y2)is given by the formula:
m=Δy/Δx=y2-y1/x2-x1
So the slopes of the sides of our quadrilateral are:
mJK=(−1)−24−(−3)=−37
mKL=(−5)−(−1)2−4=2
mLM=(−2)−(−5)−5−2=−37
mMJ=2−(−2)(−3)−(−5)=2
So JK is parallel to LM and KL is parallel to MJ
So JKLM is a parallelogram.
Answer:
Step-by-step explanation:
Answer: 2/25
Step-by-step explanation:
The formula to find the slope is (y2-y1)/(x2-x1)
If you plug in the numbers, you get (18-14)/(30-(-20))
Solve the expression and you get 4/50 = 2/25
So your answer is 2/25
