Answer:
x=80
Step-by-step explanation:
im going to assume this is perimeter.
50+50=100
260-100=160
160÷2=80
Answer A is the only one that seems to make sense to me id choose A
The answer is 1 2/3 hope this helped
Answer:
(1 ) Inner curved surface area of the well is 109.9 sq. meters.
(2) The cost of plastering the total curved surface area is 4396.
Step-by-step explanation:
The inner diameter = 3.5 m
Depth of the well = 10 m
Now, Diameter = 2 x Radius
⇒R = D/ 2 = 3.5/2 = 1.75
or, the inner radius of the well = 1.75 m
CURVED SURFACE AREA of cylinder = 2πr h
⇒The inner curved surface area = 2πr h = 2 ( 3.14) (1.75)(10)
= 109 sq. meters
Hence, the inner curved surface area of the well is 109.9 sq. meters.
Now, the cost of plastering the curved area is 40 per sq meters
So, the cost of total plastering total area = 109.9 x(Cost per meter sq.)
= 109.9 x (40)
= 4396
Hence, the cost of plastering the total curved surface area is 4396.
Answer:
C
Step-by-step explanation:
1. press 9
2. then the exponet key
3. then press 6
4. finally press the equal sign (=)
