3 years ago

What are some numbers that have an absolute value greater than 2 1/2

Mathematics

1 answer:

Ilya [14]3 years ago

8 0

-3, 28, 500, 64, -10, -25 these al have greater absolute values than 2 1/2

You might be interested in

Let f(x) = -4x + 7 and g(x) = 10x - 6 find f(g(x))

max2010maxim [7]

F(x) = -4x + 7
g(x) = 10x - 6

f(g(x)) = -4(10x - 6) + 7
f(g(x)) = -4(10x) + 4(6) + 7
f(g(x)) = -40x + 24 + 7
f(g(x)) = -40x + 31

7 0

2 years ago

Read 2 more answers

A function f(x) is graphed on the coordinate plane.

ella [17]

Your answer is Y= 0x-2b .
This is because it hits -2 on the y axis.

6 0

2 years ago

Read 2 more answers

Points 50

pogonyaev

-2x + 4.4 = 23.8

Subtract 4.4 from both sides

-2x = 19.4

Divide both sides by-2:

X = -9.7

Answer: C. -9.7

8 0

2 years ago

Read 2 more answers

Which number is equal to 15 a)0.015 b)1.5 c)150/100 d)3/20

myrzilka [38]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Choose the appropriate pattern and use it to find the product: (p4−q4)(p4+q4).

sp2606 [1]

The expression can be solved by expanding the bracket and multiplying out the terms

$(p^4-q^4)(p^4+q^4)$ $\begin{gathered} =p^4(p^4+q^4)-q^4(p^4+q^4) \\ =p^8+p^4q^4-p^4q^4-q^8 \\ =p^8-q^8 \end{gathered}$

Therefore, the expression can be simplified as;

$p^8-q^8$

Alternatively, using the theorem of difference of two squares, which is

$a^2-b^2=(a-b)(a+b)$

Hence,

$p^8-q^8=(p^4)^2-(q^4)^2$

7 0

1 year ago