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zepelin [54]
3 years ago
13

List the perfect squares between 50 and 200. Find each spare root.

Mathematics
1 answer:
vazorg [7]3 years ago
5 0
Sqrt 64 is 8,
sqrt 81 is 9
sqrt 100 is 10,
sqrt 121 is 11,
sqrt 144 is 12,
sqrt 169 is 13,
and sqrt 196 is 14.
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Multiply 5 4/7 x -2 2/5
Lunna [17]
Hey i hope my answer is helpful i did in my head so im sorry if its wrong−13 13/35
4 0
3 years ago
A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest
faltersainse [42]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396

add both amounts, and that's her investment for the 11 years.
7 0
3 years ago
CAN SOMONE PLEASE HELP ME ASAP PLEASEEE!!!​
Vlad1618 [11]

Answer:

The yellow polygon is the scaled version of the red one (scaled by 3×), so the variable w = 9

5 0
3 years ago
Read 2 more answers
I've been trying to get an answer for this all day and don't know where to begin what is the answer like I have no clue ​
Shtirlitz [24]

so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.

we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.

\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78

6 0
3 years ago
PLEASE HELP ME, ITS DUE RN
madam [21]

Answer:

here you go

Step-by-step explanation:

35+a+b+c=270

35+a=90

a+b=180

35+90+c=180

4 0
2 years ago
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