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3 years ago

Add three fraction together to get a whole number using the numbers 1-9 only once

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

3 0

Answer:

Step-by-step explanation:

1/4 + 2/8 + 3/6 = 1

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Multiple Choice: Please select the best answer and click "submit."

Vinvika [58]

I would say- f(x)=6x+2

8 0

3 years ago

Sophie pays m dollars to rent a car for the weekend on the drive home she buys $45 worth of gasoline her friend melody pays for

Hoochie [10]

Complete Question

Sophie pays m dollars to rent a car for the weekend. On the drive home, she buys $45 worth of gasoline. Her friend Melody pays for one-half the cost of the car rental only. Write an expression you could use to determine how much Sophie spent.

Answer:

1/2m + 45

Step-by-step explanation:

We are told in the question that:

On the drive home, she buys $45 worth of gasoline.

Her friend Melody pays for one-half the cost of the car rental only.

Sophie pays m dollars to rent a car for the weekend.

The amount sophie pays for car rental = m - 1/2m

= 1/2m

Therefore, the expression used to determine how much sophie spent is written as:

1/2 × $m + $45

1/2m + 45

4 0

3 years ago

find the spectral radius of A. Is this a convergent matrix? Justify your answer. Find the limit x=lim x^(k) of vector iteration

Natasha_Volkova [10]

Answer:

The solution to this question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

$A = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right]$

now for given values:

$\left[\begin{array}{ccc} \frac{3}{4} - \lambda & \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2} - \lambda & 0\\ -\frac{1}{4}& -\frac{1}{4} & 0 -\lambda \end{array}\right]=0 \\\\$

$\to (\frac{3}{4} - \lambda ) [-\lambda (\frac{1}{2} - \lambda ) -0] - 0 - \frac{1}{4}[0- \frac{1}{2} (\frac{1}{2} - \lambda )] =0 \\\\\to (\frac{3}{4} - \lambda ) [(\frac{\lambda}{2} + \lambda^2 )] - \frac{1}{4}[\frac{\lambda}{2} - \frac{1}{4}] =0 \\\\\to (\frac{3}{8}\lambda + \frac{3}{4} \lambda^2 - \frac{\lambda^2}{2} - \lambda^3 - \frac{\lambda}{8} + \frac{1}{16}=0 \\\\\to (\lambda - \frac{1}{2}) (\lambda -\frac{1}{4}) (\lambda - \frac{1}{2}) =0\\\\$

$\to \lambda_1=\lambda_2 =\frac{1}{2}\\\\\to \lambda_3 = \frac{1}{4} \\\\\to A = max {|\lambda_1| , |\lambda_2|, |\lambda_3|}\\\\$

$= max{\frac{1}{2}, \frac{1}{2}, \frac{1}{4}}\\\\= \frac{1}{2}\\\\(A) =\frac{1}{2}$

In point b:

Its

spectral radius is less than 1 hence matrix is convergent.

In point c:

$\to c^{(k+1)} = A x^{k}+C \\\\\to x(0) = \left(\begin{array}{c}3&1&2\end{array}\right) , c = \left(\begin{array}{c}2&2&4\end{array}\right)\\\\ \to x^{(k+1)} = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right] x^k + \left[\begin{array}{c}2&2&4\end{array}\right] \\\\$

after solving the value the answer is

$\lim_{k \to \infty} x^k=o = \left[\begin{array}{c}0&0&0\end{array}\right]$

4 0

3 years ago

Cody ate 170.10 grams of chicken for dinner. His sister ate 170.1 grams of chicken. Which statement is true? A. Cody and his sis

8090 [49]

A. They both ate the same because 170.10 is equal to 170.1

7 0

3 years ago

Read 2 more answers

Solve for m please. No explanation needed thank you.

liq [111]

Answer is below.

(Note to asker: Lack of explanations can get my answer deleted)

Step 1

We'll to isolate the variable, but to do that, get rid of the coefficient that multiplies it.

To do that, divide both sides by 22.

$\frac{22m}{22}=\frac{22}{10}$

Step 2.

Now we have divided both sides by 22, but we'll need to reduce the fraction $\frac{22m}{22}$ .

We can reduce the fraction by dividing the factors that are in the numerator and denominator.

That being said, 22 appears both in the numerator and denominator.

$\frac{22m}{22}=m=\frac{2\times5}{2\times11}$

Step 3

Now, for $\frac{2\times5}{2\times11}$ , we'll need to reduce it to the lowest terms. Like in the 2nd step, we'll divide factors that are in the numerator and denominator.

That being said, 2 appears both in the numerator and denominator.

Hence, M = 5/11

3 0

3 years ago