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Ipatiy [6.2K]
3 years ago
7

Need help ASAP thanks!

Mathematics
1 answer:
kherson [118]3 years ago
4 0

Answer:

it's 11.

Step-by-step explanation:

15(11)= 165. It's also 4 less than 15, which is the length.

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Please help me quick!!
ki77a [65]

Answer: how many hours is she working

Step-by-step explanation:

8 0
3 years ago
A trapezoid has an area of 13.5 square inches. If the bases are 3 and 6 inches what is the height?
liraira [26]
Well the formula is : b1+b2/2 (h)

so the height would be solved as : 
13.5 = 3+6/2 (h)
13.5 = 9/2 (h)
h = (13.5)/(9/2)
h = (13.5) x (2/9)  *reciprocal*
h = (27) / (9)
h = 3


5 0
3 years ago
8416 + 0.28 + 1.489<br> What’s the answer?
Sphinxa [80]

Answer:

8,417.769

8416 + 0.28 is just adding 28 at the end so 8416.28

now 8416.28 + 1.489 is 8,417.769

the awnser is 8,417.769



Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula
Ilia_Sergeevich [38]

Answer: A. A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}

              B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

A=\pi.r^{2}

So to find the rate of the area:

\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}

\frac{dA}{dr} =2.\pi.r

Using r(t)=3-\frac{363}{(t+11)^{2}}

\frac{dr}{dt}=\frac{726}{(t+11)^{3}}

Then

\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]

\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}

Multipying and simplifying:

\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}

The rate at which the area is increasing is given by expression A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}.

B. At t = 5, rate is:

A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}

A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}

A'(5)=\frac{2408693760\pi}{4294967296}

A'(5)=1.76268

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0
3 years ago
Solve. −3/5x +1/5 &gt; 7/20
Reika [66]
-3/5x + 1/5 > 7/20
-3/5x > 7/20 - 1/5
-3/5x > 7/20 - 4/20
-3/5x > 3/20
x < 3/20 * - 5/3
x < -15/60 reduces to -1/4

3 0
3 years ago
Read 2 more answers
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