<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>
Answer:
(5,2)
Step-by-step explanation:
Answer:
- D. A translation 1 unit to the right followed by a 270-degree counterclockwise rotation about the origin
Step-by-step explanation:
<em>See the picture for better visual</em>
Take segments ST and S'T'. If we extend them they will intersect at right angle.
It is the indication that the rotation is 90° or 270° but not 180°, when the corresponding segments come parallel.
The QRST is in the quadrant IV and Q'R'S'T' is in the quadrant III, which mean the rotation is 90° clockwise or 270° counterclockwise.
<u>This rotation rule is:</u>
We also see the points S and T have x-coordinate of 5 but their images have y-coordinates of -6. It means the translation to the right by 1 unit was the step before rotation.
<u>We now can conclude the correct choice is D:</u>
- A translation 1 unit to the right followed by a 270-degree counterclockwise rotation about the origin
Answer:
(x, y) = (-2, -3)
WORK:
2x + 4y = -16 =
-2x + 2y = -2 =
(^ the two’s cancel out) =
6y = -18 =
(^ you need to divide 6 on both sides to get just y) =
6y/6 = -18/6 =
(^ the six’s cancel out) =
y = -3 =
(^ now you have to plug this in to get x) =
2x + 4(-3) = -16 =
2x - 12 = -16 =
(^ you need to add 12 on both sides to get rid of it on the left side to add it to -16 on the right side) =
2x = -4 =
2x/2 = -4/2 =
(^ now you divide 2 on both sides again to get just y, and they will cancel out) =
x = -2 =
THEREFORE YOU GET (-2, -3)