All categories

3 years ago

Please answer this!! I will give you brainlist and 5 stars!

Mathematics

1 answer:

alexdok [17]3 years ago

8 0

Answer:

The answer is C

Step-by-step explanation:

3 BC = EF

3 AC = DF

You might be interested in

Given that y varies directly with x in the table below, what is the value of y if the value of x is 7?

Paha777 [63]

Answer:

y = 42

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use an ordered pair from the table.

Using x = 2 when y = 12, then

12 = 2k ( divide both sides by 2 )

6 = k

y = 6x ← equation of variation

When x = 7, then

y = 6 × 7 = 42

4 0

3 years ago

Read 2 more answers

Match each form with its equation.

Rasek [7]

Answers

1.Slope-intercept form
2.Point-Slope form
3.Standard Form
4.Vertical Line
5.Horizonal Line

7 0

3 years ago

a red lamp flashes every 10 seconds ,a yellow lamp flashes every 24 seconds and a blue lamp flashes every 30 seconds.How many ti

jeka57 [31]

Answer:

600x

Step-by-step explanation:

10 x 24x 30 - 10x 60x

7 0

3 years ago

PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.

worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, $m\angleK=60^\circ$ , and $m\angle M= 45^\circ$

Refer the attached image.

In a triangle sum of three angles should be $180^\circ$ .

So,

$m\angle K+m\angle L+m\angle M=180^\circ$

Plugging the values of angle K and angle M, we get:

$60^\circ+m\angle L+45^\circ=180^\circ$

So,

$m\angle L=180^\circ-105^\circ=75^\circ$

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

$\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}$

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}$

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}$

We get the value of 'y'

$y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38$

So the length of the side KM is 13.38 units.

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}$

We get the value of 'x'

$x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79$

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM $= KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17$ units

6 0

3 years ago

Read 2 more answers

Which statement about the angles in the figure is true?<br> Helppp

igomit [66]

9514 1404 393

Answer:

m∠1 +m∠8 = 90°

Step-by-step explanation:

There is no necessary sum relation between angles 3 and 5 or angles 7 and 10. The only thing you can say about those angle pairs is ...

∠3 + 90° = ∠5

∠10 +90° = ∠7

Angles 8 and 9 are congruent, so don't have any necessary sum.

Angle 1 is congruent with angle 3, which is complementary to angle 8, so we must have ...

m∠1 +m∠8 = 90°

6 0

3 years ago

Read 2 more answers