Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X 
N (µ, σ²), then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
30x³ + 35x² + 10x factorised is 5x(2x + 1)(3x +2). To find this, you first want to take out a common factor to be left with a quadratic equation. In this case, we can factor out 5x to be left with 6x² + 7x + 2.
Now we can factorise 6x² + 7x + 2 by finding factors of 6 that add together to make 7 when one of them is multiplied by 2. These are 3 and 2, which is how we end up with (2x + 1) and (3x + 2). Let me know if you would like me to go more indepth about how I found this.
Then you just put these with the 5x and you get 5x(2x + 1)(3x + 2), which are possible expressions for the length, width, and height.
I hope this helps!
Answer:
1193.2 sq. in.
Step-by-step explanation:
SA = LA + 2B
where LA is the lateral area and B is the area of the base (circle)
B = πr^2 = 3.14(10)^2 = 3.14(100) = 314
Area of 2 Bases = 2 (314) = 628
LA = Ch where C is the circumference of the base
LA = πdh = 3.14(20)(9) = 565.2
SA = 628 + 565.2 = 1193.2 sq. in.
Answer:
8
Step-by-step explanation:
crossmultiply x
If you are multiplying 16 times 2 then 32 would be your answer. If you are subtracted your answer would be 14. If you are adding them your answer would be 18. I don’t really see what sign is being used.
