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3 years ago

Radical 6x^2 multiplied by radical 18x^2

Mathematics

1 answer:

Alina [70]3 years ago

6 0

Does radical mean square root?, because radical can mean square root, cube root, fourth root, etc.

Well, I'm going to assume that radical = square root

So, if you have two square root functions, you can multiply the numbers within the square root, so you now have $\sqrt{48x^4}$ , which I'm not sure if you want it simplified or not

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Solve for x. (X+16) (4x-5) X = 4.3 X = -7 X = 3 X = 7

jeka94

Answer:

the answer is x = 7

Step-by-step explanation:

1) replace the x with 7

2) 7 + 16 = 23

3) 4(7) = 28

4) 28 - 5 = 23

they're both equal as perpendicular angles should be!

7 0

3 years ago

Find the difference 10 - ( – 25 )

sergey [27]

There is no difference they are both negative numbers or we could say 25 is higher number then 10 but it negative

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2 years ago

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Write in exponential form. 2•2•2•x•x

Sholpan [36]

2 to the 3rd power (2^3) times x to the second (x^2)

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3 years ago

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A small greeting card company prints and ships greeting cards throughout the year. Rodney is able to package and ship 416 cards

Rasek [7]

Answer:

52 cards/hour

Step-by-step explanation:

416 cards

Rodney's card production rate is --------------- = 52 cards/hour

8 hours

3 0

2 years ago

What is the nth term?

kumpel [21]

Let $a_k$ denote the kth term of the sequence. Then

$a_k=a_1+d(k-1)$

where d is the common difference between consecutive terms in the sequence and a₁ is the first term.

The sum of the first n terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the nth term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago